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PROBLEM

Evaluate the following formula for xˉ1=27.6106,xˉ2=25.9487,μ1μ2=0,s1=43.83,s2=43.83,n1=40\bar{x}_{1}=27.6106, \bar{x}_{2}=25.9487, \mu_{1}-\mu_{2}=0, s_{1}=43.83, s_{2}=43.83, n_{1}=40, and n2=43n_{2}=43.
t=(xˉ1xˉ2)(μ1μ2)s12n1+s22n2t=\frac{\left(\bar{x}_{1}-\bar{x}_{2}\right)-\left(\mu_{1}-\mu_{2}\right)}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}} t=t= \square (Round to two decimal places as needed.)

STEP 1

1. We are given the values: xˉ1=27.6106\bar{x}_{1}=27.6106, xˉ2=25.9487\bar{x}_{2}=25.9487, μ1μ2=0\mu_{1}-\mu_{2}=0, s1=43.83s_{1}=43.83, s2=43.83s_{2}=43.83, n1=40n_{1}=40, and n2=43n_{2}=43.
2. The formula to evaluate is:
$$ t=\frac{\left(\bar{x}_{1}-\bar{x}_{2}\right)-\left(\mu_{1}-\mu_{2}\right)}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}
\] 3. The result should be rounded to two decimal places.

STEP 2

1. Calculate the numerator of the formula.
2. Calculate the denominator of the formula.
3. Evaluate the formula and round the result.

STEP 3

Calculate the numerator:
(xˉ1xˉ2)(μ1μ2)=(27.610625.9487)0=1.6619\left(\bar{x}_{1}-\bar{x}_{2}\right) - \left(\mu_{1}-\mu_{2}\right) = (27.6106 - 25.9487) - 0 = 1.6619

STEP 4

Calculate the denominator:
s12n1+s22n2=43.83240+43.83243\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}} = \sqrt{\frac{43.83^2}{40} + \frac{43.83^2}{43}} Calculate each term:
43.83240=1921.188940=48.0297225\frac{43.83^2}{40} = \frac{1921.1889}{40} = 48.0297225 43.83243=1921.188943=44.6741628\frac{43.83^2}{43} = \frac{1921.1889}{43} = 44.6741628 Add the terms:
48.0297225+44.6741628=92.703885348.0297225 + 44.6741628 = 92.7038853 Take the square root:
92.70388539.6304\sqrt{92.7038853} \approx 9.6304

SOLUTION

Evaluate the formula:
t=1.66199.63040.1725t = \frac{1.6619}{9.6304} \approx 0.1725 Round to two decimal places:
t0.17t \approx 0.17 The value of t t is:
0.17 \boxed{0.17}

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