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Math

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PROBLEM

Evaluate (gf)(2)(g \circ f)(2) where f(x)=x37xf(x)=x^{3}-7x and g(x)=5xg(x)=\sqrt{5x}.

STEP 1

Assumptions1. We have three functions f(x)=x37xf(x)=x^{3}-7 x, g(x)=5xg(x)=\sqrt{5 x}, and h(x)=x5h(x)= x-5.
. We need to evaluate the function (gf)(x)(g \circ f)(x) for x=x=.
3. The notation (gf)(x)(g \circ f)(x) means that we first apply the function ff to xx, and then apply the function gg to the result.

STEP 2

First, we need to evaluate the function f(x)f(x) at x=2x=2. This is done by substituting x=2x=2 into the function f(x)f(x).
f(2)=272f(2)=2^{}-7 \cdot2

STEP 3

Calculate the value of f(2)f(2).
f(2)=2372=814=6f(2)=2^{3}-7 \cdot2 =8 -14 = -6

STEP 4

Now that we have the value of f(2)f(2), we can substitute this value into the function g(x)g(x) to evaluate (gf)(2)(g \circ f)(2).
g(f(2))=g(6)g(f(2))=g(-6)

STEP 5

Substitute x=x=- into the function g(x)g(x).
g()=5g(-)=\sqrt{5 \cdot -}

SOLUTION

Calculate the value of g(6)g(-6).
Since the square root of a negative number is not a real number, g(6)g(-6) is undefined in the real number system. Therefore, (gf)(2)(g \circ f)(2) is also undefined.
(gf)(2)(g \circ f)(2) is undefined.

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