Math  /  Calculus

QuestionEvaluate the limit: limx04x+497x=\lim _{x \rightarrow 0} \frac{\sqrt{4 x+49}-7}{x}= \square

Studdy Solution

STEP 1

What is this asking? We need to find what the expression approaches as xx gets really close to 0. Watch out! If we just plug in x=0x = 0, we get 00\frac{0}{0}, which is undefined!
So, we need a clever trick.

STEP 2

1. Rewrite the expression
2. Evaluate the limit

STEP 3

Let's multiply the expression by 11 in a sneaky way.
We'll use the conjugate of the numerator: 4x+49+7\sqrt{4x + 49} + 7.
This will help us simplify the expression!

STEP 4

limx04x+497x=limx0(4x+49)49x(4x+49+7)=limx04xx(4x+49+7)\begin{aligned} \lim_{x \rightarrow 0} \frac{\sqrt{4x + 49} - 7}{x} &= \lim_{x \rightarrow 0} \frac{(4x + 49) - 49}{x(\sqrt{4x + 49} + 7)} \\ &= \lim_{x \rightarrow 0} \frac{4x}{x(\sqrt{4x + 49} + 7)} \end{aligned}

STEP 5

Now, we can divide both the numerator and denominator by xx (since xx is approaching 0, it's not equal to 0, so this is valid). limx04xx(4x+49+7)=limx044x+49+7\lim_{x \rightarrow 0} \frac{4x}{x(\sqrt{4x + 49} + 7)} = \lim_{x \rightarrow 0} \frac{4}{\sqrt{4x + 49} + 7} Look at that, the pesky xx in the denominator is gone!

STEP 6

Now we can substitute x=0x = 0 into the simplified expression: limx044x+49+7=440+49+7\lim_{x \rightarrow 0} \frac{4}{\sqrt{4x + 49} + 7} = \frac{4}{\sqrt{4 \cdot 0 + 49} + 7}

STEP 7

449+7=47+7=414=27\frac{4}{\sqrt{49} + 7} = \frac{4}{7 + 7} = \frac{4}{14} = \frac{2}{7} Boom!

STEP 8

The limit is 27\frac{2}{7}.

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