Math  /  Trigonometry

QuestionExample 6: Emma is on a 50 meter high bridge and sees two boats anchored below. From her position, boat A has a bearing of 230230^{\circ} and boat BB has a bearing of 120120^{\circ}. Emma estimates the angles of depression to be 3838^{\circ} for boat A and 3535^{\circ} for boat B. How far apart are the boats to the nearest meter?

Studdy Solution

STEP 1

1. The height of the bridge is 50 50 meters.
2. The angles of depression to boats A and B are 38 38^{\circ} and 35 35^{\circ} respectively.
3. Bearings are measured clockwise from the north direction.

STEP 2

1. Understand the relationship between angles of depression and horizontal distances.
2. Calculate the horizontal distances from Emma to each boat.
3. Use trigonometry to find the positions of the boats relative to each other.
4. Calculate the distance between the two boats using the Law of Cosines.

STEP 3

Understand that the angle of depression from Emma to a boat is equal to the angle of elevation from the boat to Emma. This means we can use trigonometry to find the horizontal distance from Emma to each boat.

STEP 4

Calculate the horizontal distance from Emma to boat A using the angle of depression:
Let dA d_A be the horizontal distance to boat A. tan(38)=50dA \tan(38^{\circ}) = \frac{50}{d_A} dA=50tan(38) d_A = \frac{50}{\tan(38^{\circ})}
Calculate dA d_A .

STEP 5

Calculate the horizontal distance from Emma to boat B using the angle of depression:
Let dB d_B be the horizontal distance to boat B. tan(35)=50dB \tan(35^{\circ}) = \frac{50}{d_B} dB=50tan(35) d_B = \frac{50}{\tan(35^{\circ})}
Calculate dB d_B .

STEP 6

Use trigonometry to find the positions of the boats relative to each other. The bearings provide angles with respect to the north direction:
- Boat A is at a bearing of 230 230^{\circ} . - Boat B is at a bearing of 120 120^{\circ} .
Calculate the angle between the two bearings:
Angle between bearings=230120=110 \text{Angle between bearings} = 230^{\circ} - 120^{\circ} = 110^{\circ}

STEP 7

Use the Law of Cosines to find the distance between the two boats:
Let c c be the distance between the boats. c2=dA2+dB22dAdBcos(110) c^2 = d_A^2 + d_B^2 - 2 \cdot d_A \cdot d_B \cdot \cos(110^{\circ})
Calculate c c and round to the nearest meter.
The distance between the boats is:
c meters \boxed{c \text{ meters}}

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