Math  /  Data & Statistics

QuestionExercise A survey found the 21%21 \% of adults never exercise at all. A researcher selected a random sample of 120 adults and found that 21 adults said that they do not exercise at all. At α=0.05\alpha=0.05, is there sufficient evidence that less than 21%21 \% of adults do not exercise at all? Use the critical value method. Do not round intermediate steps.
Part 1 of 5 (a) State the hypotheses and identify the claim. H0:p=0.21H1:p<0.21\begin{array}{l} H_{0}: p=0.21 \\ H_{1}: p<0.21 \end{array} not claim claim
This hypothesis test is a \square one-tailed test.
Part: 1/51 / 5 \square
Part 2 of 5 (b) Find the critical value. Round the answer to at least two decimal places.
The critical value is \square .

Studdy Solution

STEP 1

1. We are conducting a hypothesis test for a population proportion.
2. The null hypothesis is H0:p=0.21 H_0: p = 0.21 .
3. The alternative hypothesis is H1:p<0.21 H_1: p < 0.21 .
4. The significance level is α=0.05\alpha = 0.05.

STEP 2

1. Identify the type of test.
2. Determine the critical value for the test.

STEP 3

Identify the type of test.
Since the alternative hypothesis is H1:p<0.21 H_1: p < 0.21 , this is a left-tailed test.

STEP 4

Determine the critical value.
For a left-tailed test at α=0.05\alpha = 0.05, we find the critical value using the standard normal distribution (Z-distribution).
The critical value zα z_{\alpha} corresponds to the point where the cumulative probability is 0.05 0.05 .
Using a Z-table or calculator, the critical value for α=0.05\alpha = 0.05 is approximately:
zα=1.645 z_{\alpha} = -1.645
The critical value is:
1.645 \boxed{-1.645}

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