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Math

Math Snap

PROBLEM

Expand: ln2a3b4\ln \frac{2 a^{3}}{b^{4}}
ln2+3lna4lnb\ln 2+3 \ln a-4 \ln b
ln23lna4lnb\ln 2-3 \ln a-4 \ln b
ln23lna+4lnb\ln 2-3 \ln a+4 \ln b

STEP 1

What is this asking?
We need to rewrite the natural logarithm of a fraction with variables and a constant into a simpler form using logarithm rules.
Watch out!
It's easy to mess up the signs when using the logarithm rules, so let's be extra careful!

STEP 2

1. Expand the numerator
2. Expand the denominator
3. Combine the results

STEP 3

We have ln2a3b4\ln\frac{2a^3}{b^4}.
We can rewrite the numerator using the product rule for logarithms, which says ln(xy)=ln(x)+ln(y)\ln(xy) = \ln(x) + \ln(y).
So, ln(2a3)\ln(2a^3) becomes ln(2)+ln(a3)\ln(2) + \ln(a^3).
This rule helps us break down complex expressions inside the logarithm!

STEP 4

Now, let's use the power rule for logarithms, which says ln(xy)=yln(x)\ln(x^y) = y\cdot \ln(x).
Applying this to ln(a3)\ln(a^3), we get 3ln(a)3\cdot \ln(a).
So, the numerator becomes ln(2)+3ln(a)\ln(2) + 3\cdot\ln(a).
This rule helps us bring exponents down as coefficients.

STEP 5

The denominator is ln(b4)\ln(b^4).
Using the power rule for logarithms, which says ln(xy)=yln(x)\ln(x^y) = y\cdot \ln(x), we get 4ln(b)4\cdot \ln(b).

STEP 6

Our expression is now ln2a3b4=ln(2a3)ln(b4)\ln\frac{2a^3}{b^4} = \ln(2a^3) - \ln(b^4), which we've already simplified to ln(2)+3ln(a)4ln(b)\ln(2) + 3\cdot\ln(a) - 4\cdot\ln(b).

STEP 7

We've used the logarithm rules to expand everything correctly!
Our final expression is ln(2)+3ln(a)4ln(b)\ln(2) + 3\cdot\ln(a) - 4\cdot\ln(b).

SOLUTION

The expanded form of ln2a3b4\ln \frac{2 a^{3}}{b^{4}} is ln2+3lna4lnb\ln 2+3 \ln a-4 \ln b.

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