Math  /  Numbers & Operations

QuestionExpress each rate in simplest form. a 10 km in 2 hours b $650\$ 650 for 13 hours c 2800 km in 20 days

Studdy Solution

STEP 1

1. Each rate is given in terms of a quantity per unit of time or cost.
2. The goal is to simplify each rate to its simplest form, meaning the smallest whole number ratio.

STEP 2

1. Simplify the distance rate.
2. Simplify the cost rate.
3. Simplify the travel rate.

STEP 3

For part (a), simplify the rate of 10 10 km in 2 2 hours.
Divide both the distance and the time by their greatest common divisor (GCD).
The GCD of 10 10 and 2 2 is 2 2 .
10 km2 hours=10÷2 km2÷2 hours=5 km1 hour \frac{10 \text{ km}}{2 \text{ hours}} = \frac{10 \div 2 \text{ km}}{2 \div 2 \text{ hours}} = \frac{5 \text{ km}}{1 \text{ hour}}

STEP 4

For part (b), simplify the rate of $650 \$650 for 13 13 hours.
Divide both the cost and the time by their greatest common divisor (GCD).
The GCD of 650 650 and 13 13 is 13 13 .
$65013 hours=650÷1313÷13 hours=$501 hour \frac{\$650}{13 \text{ hours}} = \frac{650 \div 13}{13 \div 13 \text{ hours}} = \frac{\$50}{1 \text{ hour}}

STEP 5

For part (c), simplify the rate of 2800 2800 km in 20 20 days.
Divide both the distance and the time by their greatest common divisor (GCD).
The GCD of 2800 2800 and 20 20 is 20 20 .
2800 km20 days=2800÷20 km20÷20 days=140 km1 day \frac{2800 \text{ km}}{20 \text{ days}} = \frac{2800 \div 20 \text{ km}}{20 \div 20 \text{ days}} = \frac{140 \text{ km}}{1 \text{ day}}
The simplified rates are: a. 5 km per hour 5 \text{ km per hour} b. $50 per hour \$50 \text{ per hour} c. 140 km per day 140 \text{ km per day}

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