QuestionFind $f(-4)$ using the function $f(x)=x^{2}-1$ given that $f(-2)=f(0)=f(1)=\;$ .

Studdy Solution

STEP 1

Assumptions1. The function is defined as $f(x)=x^{}-1$ . We need to find the value of $f(-4)$

STEP 2

To find the value of $f(-4)$ , we need to substitute $-4$ in place of $x$ in the function $f(x)=x^{2}-1$ .
$f(-4)=(-4)^{2}-1$

STEP 3

Calculate the square of $-$ .
$(-)^{2}=16$

STEP 4

Substitute the value of $(-4)^{2}$ into the equation.
$f(-4)=16-1$

STEP 5

Subtract1 from16 to find the value of $f(-4)$ .
$f(-4)=16-1=15$ So, $f(-4)=15$ .

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QuestionFind $f(-4)$ using the function $f(x)=x^{2}-1$ given that $f(-2)=f(0)=f(1)=\;$ .

Studdy Solution

STEP 1

Assumptions1. The function is defined as $f(x)=x^{}-1$ . We need to find the value of $f(-4)$

STEP 2

To find the value of $f(-4)$ , we need to substitute $-4$ in place of $x$ in the function $f(x)=x^{2}-1$ .
$f(-4)=(-4)^{2}-1$

STEP 3

Calculate the square of $-$ .
$(-)^{2}=16$

STEP 4

Substitute the value of $(-4)^{2}$ into the equation.
$f(-4)=16-1$

STEP 5

Subtract1 from16 to find the value of $f(-4)$ .
$f(-4)=16-1=15$ So, $f(-4)=15$ .

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QuestionFind f(−4)f(-4)f(−4) using the function f(x)=x2−1f(x)=x^{2}-1f(x)=x2−1 given that f(−2)=f(0)=f(1)= f(-2)=f(0)=f(1)=\;f(−2)=f(0)=f(1)=.

Studdy Solution

STEP 1

Assumptions1. The function is defined as f(x)=x−1f(x)=x^{}-1f(x)=x−1 . We need to find the value of f(−4)f(-4)f(−4)

STEP 2

To find the value of f(−4)f(-4)f(−4), we need to substitute −4-4−4 in place of xxx in the function f(x)=x2−1f(x)=x^{2}-1f(x)=x2−1.f(−4)=(−4)2−1f(-4)=(-4)^{2}-1f(−4)=(−4)2−1

STEP 3

Calculate the square of −-−.(−)2=16(-)^{2}=16(−)2=16

STEP 4

Substitute the value of (−4)2(-4)^{2}(−4)2 into the equation.f(−4)=16−1f(-4)=16-1f(−4)=16−1

STEP 5

Subtract1 from16 to find the value of f(−4)f(-4)f(−4).f(−4)=16−1=15f(-4)=16-1=15f(−4)=16−1=15So, f(−4)=15f(-4)=15f(−4)=15.

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QuestionFind $f(-4)$ using the function $f(x)=x^{2}-1$ given that $f(-2)=f(0)=f(1)=\;$ .

Assumptions1. The function is defined as $f(x)=x^{}-1$ . We need to find the value of $f(-4)$

To find the value of $f(-4)$ , we need to substitute $-4$ in place of $x$ in the function $f(x)=x^{2}-1$ .
$f(-4)=(-4)^{2}-1$

Calculate the square of $-$ .
$(-)^{2}=16$

Substitute the value of $(-4)^{2}$ into the equation.
$f(-4)=16-1$

Subtract1 from16 to find the value of $f(-4)$ .
$f(-4)=16-1=15$ So, $f(-4)=15$ .