Math  /  Trigonometry

Questionf. (tanθ1)(secθ1)=0(\tan \theta-1)(\sec \theta-1)=0

Studdy Solution

STEP 1

1. The equation (tanθ1)(secθ1)=0(\tan \theta - 1)(\sec \theta - 1) = 0 is a product of two factors set to zero.
2. We will use the zero-product property, which states that if a product of factors is zero, at least one of the factors must be zero.

STEP 2

1. Apply the zero-product property.
2. Solve each resulting equation for θ\theta.
3. Determine the general solutions for θ\theta.

STEP 3

Apply the zero-product property. This means setting each factor equal to zero:
tanθ1=0orsecθ1=0\tan \theta - 1 = 0 \quad \text{or} \quad \sec \theta - 1 = 0

STEP 4

Solve the first equation tanθ1=0\tan \theta - 1 = 0:
tanθ=1\tan \theta = 1
The general solution for tanθ=1\tan \theta = 1 is:
θ=π4+nπ,nZ\theta = \frac{\pi}{4} + n\pi, \quad n \in \mathbb{Z}

STEP 5

Solve the second equation secθ1=0\sec \theta - 1 = 0:
secθ=1\sec \theta = 1
Since secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}, this implies:
cosθ=1\cos \theta = 1
The general solution for cosθ=1\cos \theta = 1 is:
θ=2nπ,nZ\theta = 2n\pi, \quad n \in \mathbb{Z}

STEP 6

Combine the solutions from both equations to determine the complete set of solutions for θ\theta:
1. θ=π4+nπ,nZ\theta = \frac{\pi}{4} + n\pi, \quad n \in \mathbb{Z}
2. θ=2nπ,nZ\theta = 2n\pi, \quad n \in \mathbb{Z}

These solutions represent the angles where either tanθ=1\tan \theta = 1 or secθ=1\sec \theta = 1.
The general solutions for θ\theta are:
θ=π4+nπandθ=2nπ,nZ\boxed{\theta = \frac{\pi}{4} + n\pi \quad \text{and} \quad \theta = 2n\pi, \quad n \in \mathbb{Z}}

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