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Math

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PROBLEM

Factor completely: 25a2(a1)225 a^{2} - (a - 1)^{2}.

STEP 1

Assumptions1. We are given the expression 25a(a1)25a^{} - (a-1)^{}.
. We are asked to factorise it completely.

STEP 2

The given expression can be rewritten as a difference of two squares. The difference of two squares is a term in algebra where it is the subtraction of the squares of two terms. It can be factorised as (a+b)(ab)(a+b)(a-b).
$$25a^{2} - (a-1)^{2}
$$

STEP 3

We can rewrite 25a225a^{2} as (5a)2(5a)^{2} and (a1)2(a-1)^{2} as it is.
$$(5a)^{2} - (a-1)^{2}
$$

STEP 4

Now, we can apply the formula for the difference of two squares, which is (a+b)(ab)(a+b)(a-b).
$$(a + (a-1))(a - (a-1))
$$

SOLUTION

implify the expressions within the brackets.
$$(a -1)(4a +1)
$$So, the factorised form of the given expression $25a^{2} - (a-1)^{2}$ is $(a -1)(4a +1)$.

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