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Math

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PROBLEM

Figure 1
Figure 2
In Figure 1, a block of mass mm has speed vv when it reaches the bottom of a ramp. When the block reaches the top of the ramp, the height of the block has increased by hh and the gravitational potential energy of the block-Earth system has changed by an amount ΔUg1\Delta U_{g 1}. In Figure 2 , a block of mass 2m2 m has speed v/2v / 2 when it reaches the bottom of the same ramp. When the block reaches the top of the ramp, the height of the block increases by hh and the gravitational potential energy of the block-Earth system changes by an amount ΔUg2\Delta U_{g 2}. Which of the following correctly relates ΔUg2\Delta U_{g 2} to ΔUg1\Delta U_{g 1} ?

STEP 1

1. The gravitational potential energy change is given by ΔUg=mgh\Delta U_g = mgh.
2. The height increase hh is the same for both scenarios.
3. The gravitational acceleration gg is constant.

STEP 2

1. Express the change in gravitational potential energy for Figure 1.
2. Express the change in gravitational potential energy for Figure 2.
3. Relate ΔUg2\Delta U_{g 2} to ΔUg1\Delta U_{g 1}.

STEP 3

Express the change in gravitational potential energy for Figure 1:
The change in gravitational potential energy for the block in Figure 1 is:
ΔUg1=mgh\Delta U_{g 1} = mgh

STEP 4

Express the change in gravitational potential energy for Figure 2:
The change in gravitational potential energy for the block in Figure 2 is:
ΔUg2=(2m)gh=2mgh\Delta U_{g 2} = (2m)gh = 2mgh

SOLUTION

Relate ΔUg2\Delta U_{g 2} to ΔUg1\Delta U_{g 1}:
Since ΔUg1=mgh\Delta U_{g 1} = mgh and ΔUg2=2mgh\Delta U_{g 2} = 2mgh, we have:
ΔUg2=2×ΔUg1\Delta U_{g 2} = 2 \times \Delta U_{g 1} The relationship between ΔUg2\Delta U_{g 2} and ΔUg1\Delta U_{g 1} is:
ΔUg2=2ΔUg1\boxed{\Delta U_{g 2} = 2 \Delta U_{g 1}}

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