PROBLEM
Fill in each blank.
6+56+256+1256…limn→∞an=limn→∞Sn= □
□
STEP 1
1. The sequence given is a geometric series.
2. The general form of a geometric series is a+ar+ar2+ar3+….
3. The sum of an infinite geometric series S is given by S=1−ra, where ∣r∣<1.
STEP 2
1. Identify the first term a and the common ratio r of the series.
2. Determine the limit of the sequence term an as n→∞.
3. Determine the sum of the infinite series Sn.
STEP 3
Identify the first term a and the common ratio r of the series:
The series is 6+56+256+1256+….
The first term a=6.
The common ratio r is found by dividing the second term by the first term:
r=656=51
STEP 4
Determine the limit of the sequence term an as n→∞:
The general term of the sequence an=6(51)n−1.
As n→∞, the term (51)n−1→0.
Thus, limn→∞an=0.
SOLUTION
Determine the sum of the infinite series Sn:
The sum of an infinite geometric series is given by:
S=1−ra=1−516=546=6×45=430=7.5 Thus, limn→∞Sn=7.5.
The completed blanks are:
1. limn→∞an=0
2. limn→∞Sn=7.5
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