Math  /  Calculus

QuestionFind (12x+5)2dx\int(12 x+5)^{2} d x (12x+5)2dx=\int(12 x+5)^{2} d x=

Studdy Solution

STEP 1

1. We are dealing with an indefinite integral.
2. The integrand is a polynomial expression raised to a power.
3. We will use substitution to simplify the integration process.

STEP 2

1. Use substitution to simplify the integrand.
2. Integrate the simplified expression.
3. Substitute back to the original variable.

STEP 3

To simplify the integration process, use substitution. Let:
u=12x+5 u = 12x + 5
Then, differentiate u u with respect to x x :
dudx=12 \frac{du}{dx} = 12
This implies:
du=12dx du = 12 \, dx
Therefore, we can express dx dx in terms of du du :
dx=112du dx = \frac{1}{12} \, du
Substitute u u and dx dx into the integral:
(12x+5)2dx=u2112du \int (12x + 5)^2 \, dx = \int u^2 \cdot \frac{1}{12} \, du
=112u2du = \frac{1}{12} \int u^2 \, du

STEP 4

Now, integrate the simplified expression:
112u2du \frac{1}{12} \int u^2 \, du
The integral of u2 u^2 with respect to u u is:
u2du=u33+C \int u^2 \, du = \frac{u^3}{3} + C
where C C is the constant of integration.
Thus, the integral becomes:
112(u33)+C \frac{1}{12} \cdot \left( \frac{u^3}{3} \right) + C
=136u3+C = \frac{1}{36} u^3 + C

STEP 5

Substitute back the original expression for u u :
u=12x+5 u = 12x + 5
So, the integral becomes:
136(12x+5)3+C \frac{1}{36} (12x + 5)^3 + C
The indefinite integral is:
136(12x+5)3+C \boxed{\frac{1}{36} (12x + 5)^3 + C}

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