Math  /  Algebra

QuestionFind a polar equation for the curve represented by the given Cartesian equation. (Assume 0θ<2π0 \leq \theta<2 \pi.) x2+y2=6yx^{2}+y^{2}=6 y

Studdy Solution

STEP 1

1. The given Cartesian equation is x2+y2=6y x^2 + y^2 = 6y .
2. We need to convert this equation into polar coordinates.
3. The polar coordinates are related to Cartesian coordinates by the equations x=rcosθ x = r \cos \theta and y=rsinθ y = r \sin \theta .
4. The equation x2+y2=r2 x^2 + y^2 = r^2 holds in polar coordinates.

STEP 2

1. Express the Cartesian equation in terms of polar coordinates.
2. Simplify the polar equation.

STEP 3

Start by substituting the polar coordinate expressions for x x and y y into the Cartesian equation:
x2+y2=6y x^2 + y^2 = 6y
Substitute x=rcosθ x = r \cos \theta and y=rsinθ y = r \sin \theta :
(rcosθ)2+(rsinθ)2=6(rsinθ) (r \cos \theta)^2 + (r \sin \theta)^2 = 6(r \sin \theta)

STEP 4

Simplify the equation using the identity x2+y2=r2 x^2 + y^2 = r^2 :
r2=6rsinθ r^2 = 6r \sin \theta

STEP 5

To solve for r r , divide both sides by r r , assuming r0 r \neq 0 :
r=6sinθ r = 6 \sin \theta
The polar equation for the curve is:
r=6sinθ r = 6 \sin \theta

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