QuestionFind $c$ using the formula $d=(r-c) t$ for $d=26$ , $r=15$ , and $t=2$ . $c=$

Studdy Solution

STEP 1

Assumptions1. The formula for the problem is $d=(r-c) t$ . The given values are $d=26$ , $r=15$ , and $t=$
3. We are solving for $c$

STEP 2

First, we need to isolate $c$ in the formula. We can do this by first dividing both sides of the equation by $t$ .
$\frac{d}{t} = r - c$

STEP 3

Now, plug in the given values for $d$ and $t$ .
$\frac{26}{2} =15 - c$

STEP 4

Calculate the left side of the equation.
$13 =15 - c$

STEP 5

To isolate $c$ , we can subtract $r$ from both sides of the equation.
$13 -15 = - c$

STEP 6

Calculate the right side of the equation.
$-2 = - c$

STEP 7

Finally, to find $c$ , we can multiply both sides of the equation by $-1$ .
$c =2$ So, $c =2$ .

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QuestionFind $c$ using the formula $d=(r-c) t$ for $d=26$ , $r=15$ , and $t=2$ . $c=$

Studdy Solution

STEP 1

Assumptions1. The formula for the problem is $d=(r-c) t$ . The given values are $d=26$ , $r=15$ , and $t=$
3. We are solving for $c$

STEP 2

First, we need to isolate $c$ in the formula. We can do this by first dividing both sides of the equation by $t$ .
$\frac{d}{t} = r - c$

STEP 3

Now, plug in the given values for $d$ and $t$ .
$\frac{26}{2} =15 - c$

STEP 4

Calculate the left side of the equation.
$13 =15 - c$

STEP 5

To isolate $c$ , we can subtract $r$ from both sides of the equation.
$13 -15 = - c$

STEP 6

Calculate the right side of the equation.
$-2 = - c$

STEP 7

Finally, to find $c$ , we can multiply both sides of the equation by $-1$ .
$c =2$ So, $c =2$ .

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QuestionFind ccc using the formula d=(r−c)td=(r-c) td=(r−c)t for d=26d=26d=26, r=15r=15r=15, and t=2t=2t=2. c=c=c=

Studdy Solution

STEP 1

Assumptions1. The formula for the problem is d=(r−c)td=(r-c) td=(r−c)t . The given values are d=26d=26d=26, r=15r=15r=15, and t=t=t=3. We are solving for ccc

STEP 2

First, we need to isolate ccc in the formula. We can do this by first dividing both sides of the equation by ttt.dt=r−c\frac{d}{t} = r - ctd​=r−c

STEP 3

Now, plug in the given values for ddd and ttt.262=15−c\frac{26}{2} =15 - c226​=15−c

STEP 4

Calculate the left side of the equation.13=15−c13 =15 - c13=15−c

STEP 5

To isolate ccc, we can subtract rrr from both sides of the equation.13−15=−c13 -15 = - c13−15=−c

STEP 6

Calculate the right side of the equation.−2=−c-2 = - c−2=−c

STEP 7

Finally, to find ccc, we can multiply both sides of the equation by −1-1−1.c=2c =2c=2So, c=2c =2c=2.

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QuestionFind $c$ using the formula $d=(r-c) t$ for $d=26$ , $r=15$ , and $t=2$ . $c=$

Assumptions1. The formula for the problem is $d=(r-c) t$ . The given values are $d=26$ , $r=15$ , and $t=$
3. We are solving for $c$

First, we need to isolate $c$ in the formula. We can do this by first dividing both sides of the equation by $t$ .
$\frac{d}{t} = r - c$

Now, plug in the given values for $d$ and $t$ .
$\frac{26}{2} =15 - c$

Calculate the left side of the equation.
$13 =15 - c$

To isolate $c$ , we can subtract $r$ from both sides of the equation.
$13 -15 = - c$

Calculate the right side of the equation.
$-2 = - c$

Finally, to find $c$ , we can multiply both sides of the equation by $-1$ .
$c =2$ So, $c =2$ .