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Math

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PROBLEM

Find 04(5x4+2)dx\int_{0}^{4}\left(5 x^{4}+2\right) d x

STEP 1

1. We are given the definite integral 04(5x4+2)dx\int_{0}^{4}\left(5 x^{4}+2\right) d x.
2. We need to evaluate this integral over the interval from x=0x = 0 to x=4x = 4.

STEP 2

1. Find the indefinite integral of the function 5x4+25x^4 + 2.
2. Evaluate the indefinite integral at the upper limit of integration.
3. Evaluate the indefinite integral at the lower limit of integration.
4. Subtract the value obtained at the lower limit from the value obtained at the upper limit to find the definite integral.

STEP 3

Find the indefinite integral of 5x4+25x^4 + 2:
(5x4+2)dx\int \left(5x^4 + 2\right) dx

STEP 4

Integrate each term separately:
5x4dx=55x4+1=x5\int 5x^4 \, dx = \frac{5}{5}x^{4+1} = x^5 2dx=2x\int 2 \, dx = 2x Combine the results:
(5x4+2)dx=x5+2x+C\int \left(5x^4 + 2\right) dx = x^5 + 2x + C

STEP 5

Evaluate the indefinite integral at the upper limit x=4x = 4:
x5+2xx=4=(4)5+2(4)x^5 + 2x \bigg|_{x=4} = (4)^5 + 2(4) Calculate the expression:
=1024+8=1032= 1024 + 8 = 1032

STEP 6

Evaluate the indefinite integral at the lower limit x=0x = 0:
x5+2xx=0=(0)5+2(0)x^5 + 2x \bigg|_{x=0} = (0)^5 + 2(0) Calculate the expression:
=0+0=0= 0 + 0 = 0

SOLUTION

Subtract the value at the lower limit from the value at the upper limit:
10320=10321032 - 0 = 1032 The value of the definite integral is:
1032\boxed{1032}

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