Math

QuestionFind the domain, range, inverse domain, and inverse range of the function f(x)=2x6f(x)=2x-6.

Studdy Solution

STEP 1

Assumptions1. The function is given as f(x)=x6f(x)=x-6 . We are looking for the domain and range of the function and its inverse.

STEP 2

The domain of a function is the set of all possible input values (usually x-values) which will produce a valid output from a particular function. For the given function f(x)=2x6f(x)=2x-6, there are no restrictions on the input values. Therefore, the domain is all real numbers.
Domainoff(x)=(,)Domain\, of\, f(x) = (-\infty, \infty)

STEP 3

The range of a function is the set of all possible output values (usually y-values), which result from the function. For the given function f(x)=2x6f(x)=2x-6, there are no restrictions on the output values. Therefore, the range is also all real numbers.
Rangeoff(x)=(,)Range\, of\, f(x) = (-\infty, \infty)

STEP 4

To find the domain and range of the inverse function, we first need to find the inverse function. The inverse of a function 'undoes' the operation of the original function. In other words, if f(x)=yf(x) = y, then f1(y)=xf^{-1}(y) = x.To find the inverse of the function f(x)=2x6f(x)=2x-6, we first replace f(x)f(x) with yy.
y=2x6y =2x -6

STEP 5

Next, we swap xx and yy to find the inverse function.
x=2yx =2y -

STEP 6

Now, solve for yy to get the inverse function.
y=x+62y = \frac{x+6}{2}So, the inverse function is f1(x)=x+62f^{-1}(x) = \frac{x+6}{2}.

STEP 7

The domain of the inverse function is the set of all possible input values (usually x-values) which will produce a valid output from the inverse function. For the given inverse function f1(x)=x+62f^{-1}(x) = \frac{x+6}{2}, there are no restrictions on the input values. Therefore, the domain is all real numbers.
Domainoff1(x)=(,)Domain\, of\, f^{-1}(x) = (-\infty, \infty)

STEP 8

The range of the inverse function is the set of all possible output values (usually y-values), which result from the inverse function. For the given inverse function f1(x)=x+62f^{-1}(x) = \frac{x+6}{2}, there are no restrictions on the output values. Therefore, the range is also all real numbers.
Rangeoff1(x)=(,)Range\, of\, f^{-1}(x) = (-\infty, \infty)So, the domain and range of the function f(x)=2x6f(x)=2x-6 and its inverse f1(x)=x+62f^{-1}(x) = \frac{x+6}{2} are all real numbers.

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