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PROBLEM

Find point PP that divides segment AB\overline{AB} with endpoints (6, 16) in ratio 4:1 and (-9, 6) in ratio 1:4.

STEP 1

Assumptions1. The endpoints of the line segment AB\overline{AB} are given.
. We need to find the coordinates of the point $$ that partitions the segment in the given ratio.
Let's start with problem15.

STEP 2

The formula to find the coordinate of a point that divides a line segment in a given ratio is=mB+nAm+n = \frac{mB + nA}{m + n}where AA and BB are the coordinates of the endpoints, and m:nm:n is the given ratio.

STEP 3

For problem15, the endpoints are6 and16, and the ratio is1. Plug these values into the formula.
=16+16+1 = \frac{ \cdot16 +1 \cdot6}{ +1}

STEP 4

Perform the multiplication in the numerator.
=64+6 = \frac{64 +6}{}

STEP 5

Add the values in the numerator.
=705 = \frac{70}{5}

STEP 6

Divide the numerator by the denominator to find the coordinate of point $$.
=70/5=14 =70 /5 =14For problem15, the coordinate of point $$ is14.
Now, let's solve problem16.

STEP 7

For problem16, the endpoints are -9 and6, and the ratio is14. Plug these values into the formula.
=16+491+4 = \frac{1 \cdot6 +4 \cdot -9}{1 +4}

STEP 8

Perform the multiplication in the numerator.
=6365 = \frac{6 -36}{5}

STEP 9

Subtract the values in the numerator.
=305 = \frac{-30}{5}

SOLUTION

Divide the numerator by the denominator to find the coordinate of point $$.
=30/5=6 = -30 /5 = -6For problem16, the coordinate of point $$ is -6.

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