Math

QuestionCalculate the area and perimeter of a rectangle with sides 58\frac{5}{8} inch and 34\frac{3}{4} inch. Simplify your answer.

Studdy Solution

STEP 1

Assumptions1. The length of the rectangle is 58\frac{5}{8} inch. The width of the rectangle is 34\frac{3}{4} inch3. The area of a rectangle is calculated by multiplying the length by the width4. The perimeter of a rectangle is calculated by adding twice the length and twice the width

STEP 2

First, we need to find the area of the rectangle. We can do this by multiplying the length by the width.
Area=LengthtimesWidthArea = Length \\times Width

STEP 3

Now, plug in the given values for the length and width to calculate the area.
Area=58times3Area = \frac{5}{8} \\times \frac{3}{}

STEP 4

Calculate the area of the rectangle.
Area=8times34=1532Area = \frac{}{8} \\times \frac{3}{4} = \frac{15}{32}

STEP 5

Next, we need to find the perimeter of the rectangle. We can do this by adding twice the length and twice the width.
Perimeter=2(Length+Width)Perimeter =2(Length + Width)

STEP 6

Plug in the given values for the length and width to calculate the perimeter.
Perimeter=2(58+34)Perimeter =2\left(\frac{5}{8} + \frac{3}{4}\right)

STEP 7

Before calculating the perimeter, simplify the expression inside the parentheses.
5+34=5+6=11\frac{5}{} + \frac{3}{4} = \frac{5}{} + \frac{6}{} = \frac{11}{}

STEP 8

Now, calculate the perimeter of the rectangle.
Perimeter=2×118=228=114=234Perimeter =2 \times \frac{11}{8} = \frac{22}{8} = \frac{11}{4} =2\frac{3}{4}So, the area of the rectangle is 1532\frac{15}{32} square inches and the perimeter is 2342\frac{3}{4} inches.

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