Math

QuestionFind the difference and express it as a+bia + b i: (18+8i)(3+3i)(-18 + 8 i) - (3 + 3 i)

Studdy Solution

STEP 1

Assumptions1. We are dealing with complex numbers, which are in the form of a+bia + bi, where aa and bb are real numbers, and ii is the imaginary unit with the property i=1i^ = -1. . We are asked to find the difference between two complex numbers (18+8i)(-18+8i) and (3+3i)(3+3i).

STEP 2

To subtract complex numbers, we subtract the real parts and the imaginary parts separately.
(a+bi)(c+di)=(ac)+(bd)i(a + bi) - (c + di) = (a - c) + (b - d)i

STEP 3

Now, plug in the given values for the complex numbers to calculate the difference.
(18+8i)(3+3i)=(183)+(83)i(-18 +8i) - (3 +3i) = (-18 -3) + (8 -3)i

STEP 4

Perform the subtraction for the real parts and the imaginary parts separately.
(183)+(83)i=21+i(-18 -3) + (8 -3)i = -21 +iSo, the difference between the two complex numbers (18+8i)(-18+8i) and (3+3i)(3+3i) is 21+i-21 +i.

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