Math

QuestionFind the line parallel to y=3x+6y=3x+6 that passes through the point (3,2)(3,2). What is its equation?

Studdy Solution

STEP 1

Assumptions1. The equation of the line we want to find is parallel to the line defined by the equation y=3x+6y=3x+6. . The line we want to find goes through the point (3,)(3,).
3. The slope of a line given by the equation y=mx+by=mx+b is mm.
4. Two lines are parallel if and only if their slopes are equal.

STEP 2

First, we need to find the slope of the given line. We can do this by identifying the coefficient of xx in the equation of the line.
The equation of the given line is y=x+6y=x+6, so the slope of the line is $$.

STEP 3

Since the line we want to find is parallel to the given line, its slope is also 33.

STEP 4

The general form of the equation of a line is y=mx+by=mx+b, where mm is the slope and bb is the y-intercept. We know that the slope of the line we want to find is 33, so the equation of the line is y=3x+by=3x+b.

STEP 5

To find the y-intercept bb, we can use the fact that the line goes through the point (3,2)(3,2). This means that when x=3x=3, y=2y=2. We can substitute these values into the equation of the line to solve for bb.
2=3(3)+b2=3(3)+b

STEP 6

olve the equation for bb.
2=9+b2=9+b

STEP 7

Subtract 99 from both sides of the equation to isolate bb.
b=29b=2-9

STEP 8

Calculate the value of bb.
b=7b=-7

STEP 9

Now that we have the y-intercept, we can write the equation of the line. Substitute 33 for mm and 7-7 for bb in the equation y=mx+by=mx+b.
y=3x7y=3x-7The equation of the line that is parallel to the line defined by the equation y=3x+6y=3x+6 and goes through the point (3,2)(3,2) is y=3x7y=3x-7.

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