Math

QuestionFind the exact value of tan(11π)\tan(11 \pi) without using a calculator.

Studdy Solution

STEP 1

Assumptions1. We are asked to find the exact value of tan(11π)\tan (11 \pi). . We know that the tangent function has a period of π\pi.

STEP 2

We use the periodicity of the tangent function to simplify the argument. Since the period of the tangent function is π\pi, we know that tan(x)=tan(x+nπ)\tan(x) = \tan(x + n\pi), where nn is any integer.
tan(11π)=tan(11π11π)\tan (11 \pi) = \tan (11 \pi -11\pi)

STEP 3

implify the expression within the tangent function.
tan(11π11π)=tan(0)\tan (11 \pi -11\pi) = \tan (0)

STEP 4

We know that the tangent of zero is zero.
tan(0)=0\tan (0) =0So, the exact value of tan(11π)\tan (11 \pi) is0.

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