Math

QuestionFind the inverse function f1f^{-1} of f(x)=(x4+4)1f(x)=\left(x^{4}+4\right)^{-1} for x(,0]x \in (-\infty, 0].

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is given by f(x)=(x4+4)1f(x)=\left(x^{4}+4\right)^{-1} for x(,0]x \in (-\infty,0] . We need to find the inverse function f1(x)f^{-1}(x)

STEP 2

To find the inverse of a function, we replace f(x)f(x) with yy.
y=(x4+4)1y = \left(x^{4}+4\right)^{-1}

STEP 3

Next, we interchange xx and yy to find the inverse.
x=(y+)1x = \left(y^{}+\right)^{-1}

STEP 4

To solve for yy, we first take the reciprocal of both sides.
1x=y4+4\frac{1}{x} = y^{4}+4

STEP 5

Subtract4 from both sides.
1x4=y4\frac{1}{x} -4 = y^{4}

STEP 6

Take the fourth root of both sides to solve for yy.y=1x44y = \sqrt[4]{\frac{1}{x} -4}

STEP 7

However, since the original function f(x)f(x) was defined for x0x \leq0, the inverse function f1(x)f^{-1}(x) must be defined for y0y \leq0. Therefore, we take the negative of the fourth root.
y=1x44y = -\sqrt[4]{\frac{1}{x} -4}So, the inverse function f1(x)f^{-1}(x) is given byf1(x)=1x44f^{-1}(x) = -\sqrt[4]{\frac{1}{x} -4}

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