Math

QuestionFind the general antiderivative of dydx=7ex+4\frac{d y}{d x}=7 e^{x}+4. Antiderivative == +C+C.

Studdy Solution

STEP 1

Assumptions1. The function given is dydx=7ex+4\frac{d y}{d x}=7 e^{x}+4 . We are asked to find the most general antiderivative of this function3. We are not to include the constant of integration +C+C in our steps, as it is understood to be included in the final answer

STEP 2

The antiderivative of a function is the function whose derivative is the given function. In this case, we need to find a function whose derivative is 7ex+47 e^{x}+4.

STEP 3

We can find the antiderivative by integrating the given function. The integral of a sum of functions is equal to the sum of the integrals of the functions. So, we can writedydxdx=(7ex+)dx=7exdx+dx\int \frac{d y}{d x} dx = \int (7 e^{x}+) dx = \int7 e^{x} dx + \int dx

STEP 4

We can now integrate each term separately. The integral of exe^{x} with respect to xx is exe^{x}, and the integral of a constant is the constant times xx. So, we have7exdx+4dx=7exdx+4dx=7ex+4x\int7 e^{x} dx + \int4 dx =7 \int e^{x} dx +4 \int dx =7 e^{x} +4xThe most general antiderivative of the function dydx=7ex+4\frac{d y}{d x}=7 e^{x}+4 is 7ex+4x+C7 e^{x} +4x + C, where CC is the constant of integration.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord