Math

QuestionFind the inverse of f(x)=x+9f(x)=-\sqrt{x+9} and specify the domain of f1(x)f^{-1}(x) in interval notation. f1(x)= f^{-1}(x)=

Studdy Solution

STEP 1

Assumptions1. The function given is f(x)=x+9f(x)=-\sqrt{x+9}. . We are required to find the inverse of this function, denoted as f1(x)f^{-1}(x).
3. We are also required to specify the domain of f1(x)f^{-1}(x) in interval notation.

STEP 2

To find the inverse of a function, we first replace f(x)f(x) with yy.
y=x+9y = -\sqrt{x+9}

STEP 3

Next, we swap xx and yy to find the inverse.
x=y+9x = -\sqrt{y+9}

STEP 4

Now, we solve for yy to find the inverse function. First, we remove the negative sign by multiplying both sides by -1.
x=y+9-x = \sqrt{y+9}

STEP 5

Next, we square both sides to remove the square root.
(x)2=(y+9)2(-x)^2 = (\sqrt{y+9})^2

STEP 6

implify the equation.
x2=y+9x^2 = y+9

STEP 7

Finally, subtract9 from both sides to solve for yy.
x29=yx^2 -9 = y

STEP 8

Replace yy with f1(x)f^{-1}(x) to get the inverse function.
f1(x)=x2f^{-1}(x) = x^2 -

STEP 9

Now, we need to find the domain of f(x)f^{-}(x). The domain of a function is the set of all possible input values (x-values) that will give real output values.

STEP 10

For the function f(x)=x29f^{-}(x) = x^2 -9, the domain is all real numbers because any real number can be squared and then subtracted by9 to give a real number.
Therefore, the domain of f(x)f^{-}(x) in interval notation is (,+)(-\infty, +\infty).
So, the inverse function of f(x)=x+9f(x)=-\sqrt{x+9} is f(x)=x29f^{-}(x) = x^2 -9 and the domain of f(x)f^{-}(x) is (,+)(-\infty, +\infty).

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