Math

QuestionFind the limit: limx2[f(x)+5g(x)]\lim _{x \rightarrow 2}[f(x)+5 g(x)] given limx2f(x)=9\lim _{x \rightarrow 2} f(x)=9 and limx2g(x)=5\lim _{x \rightarrow 2} g(x)=-5.

Studdy Solution

STEP 1

Assumptions1. The limit of f(x)f(x) as xx approaches is9. . The limit of g(x)g(x) as xx approaches is -5.
3. The limit of h(x)h(x) as xx approaches is0.
4. We are asked to find the limit of the expression [f(x)+5g(x)][f(x)+5 g(x)] as xx approaches.

STEP 2

We can use the limit laws to solve this problem. According to the limit laws, the limit of a sum or difference of two functions is the sum or difference of their limits. So, we can write the limit of the expression [f(x)+5g(x)][f(x)+5 g(x)] as the sum of the limits of f(x)f(x) and 5g(x)5g(x).
limx2[f(x)+5g(x)]=limx2f(x)+5limx2g(x)\lim{x \rightarrow2}[f(x)+5 g(x)] = \lim{x \rightarrow2}f(x) +5\lim{x \rightarrow2}g(x)

STEP 3

Now, substitute the given limits of f(x)f(x) and g(x)g(x) into the equation.
limx2[f(x)+5g(x)]=9+5(5)\lim{x \rightarrow2}[f(x)+5 g(x)] =9 +5(-5)

STEP 4

Perform the calculation to find the limit.
limx2[f(x)+g(x)]=925=16\lim{x \rightarrow2}[f(x)+ g(x)] =9 -25 = -16So, the limit of the expression [f(x)+g(x)][f(x)+ g(x)] as xx approaches2 is -16.

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