Math

QuestionFind the limits: 1) limx3x29x23x \lim _{x \rightarrow 3} \frac{x^{2}-9}{x^{2}-3 x} 2) limx33x46x+12x5+4x3 \lim _{x \rightarrow 3} \frac{3 x^{4}-6 x+12}{x^{5}+4 x^{3}}

Studdy Solution

STEP 1

Assumptions1. We are asked to find the limit of two different functions as x approaches a certain value. . We are dealing with real numbers.

STEP 2

Let's start with the first function. We need to find the limit as x approaches for the function x29x2x\frac{x^{2}-9}{x^{2}- x}.

STEP 3

First, we simplify the function. Notice that the numerator can be factored into (x3)(x+3)(x-3)(x+3) and the denominator can be factored into x(x3)x(x-3).
x29x23x=(x3)(x+3)x(x3)\frac{x^{2}-9}{x^{2}-3 x} = \frac{(x-3)(x+3)}{x(x-3)}

STEP 4

Now, we can cancel out the common factor of (x3)(x-3) from the numerator and the denominator.
(x3)(x+3)x(x3)=x+3x\frac{(x-3)(x+3)}{x(x-3)} = \frac{x+3}{x}

STEP 5

Now, we substitute x=3x =3 into the simplified function to find the limit.
limx3x+3x=3+33\lim{x \rightarrow3} \frac{x+3}{x} = \frac{3+3}{3}

STEP 6

Calculate the limit.
limx3x+3x=3+33=2\lim{x \rightarrow3} \frac{x+3}{x} = \frac{3+3}{3} =2

STEP 7

Now, let's move on to the second function. We need to find the limit as x approaches0 for the function 3x46x+12x5+4x3\frac{3 x^{4}-6 x+12}{x^{5}+4 x^{3}}.

STEP 8

First, we notice that if we substitute x=0x =0 directly into the function, we get an indeterminate form of 00\frac{0}{0}. This means we need to simplify the function first.

STEP 9

We can factor out a 33 from the numerator and an x3x^{3} from the denominator.
3x46x+12x5+4x3=3(x42x+4)x3(x2+4)\frac{3 x^{4}-6 x+12}{x^{5}+4 x^{3}} = \frac{3(x^{4}-2 x+4)}{x^{3}(x^{2}+4)}

STEP 10

Now, we substitute x=0x =0 into the simplified function to find the limit.
limx03(x42x+4)x3(x2+4)=3(0420+4)03(02+4)\lim{x \rightarrow0} \frac{3(x^{4}-2 x+4)}{x^{3}(x^{2}+4)} = \frac{3(0^{4}-2 \cdot0+4)}{0^{3}(0^{2}+4)}

STEP 11

Calculate the limit.
limx03(x4x+4)x3(x+4)=3(040+4)03(0+4)=0\lim{x \rightarrow0} \frac{3(x^{4}- x+4)}{x^{3}(x^{}+4)} = \frac{3(0^{4}- \cdot0+4)}{0^{3}(0^{}+4)} = \frac{}{0}

STEP 12

The limit as x approaches0 for the function x46x+12x5+4x\frac{ x^{4}-6 x+12}{x^{5}+4 x^{}} is undefined because we are dividing by zero.
So, the solutions are. The limit as x approaches for the function x29x2x\frac{x^{2}-9}{x^{2}- x} is2.
2. The limit as x approaches0 for the function x46x+12x5+4x\frac{ x^{4}-6 x+12}{x^{5}+4 x^{}} is undefined.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord