QuestionFind the mass of aluminum foil (length 14.79 cm, thickness 0.02 mm, density $2.71 \mathrm{~g/cm}^{3}$ ) with volume $0.4 \mathrm{~cm}^{3}$ .

Studdy Solution

STEP 1

Assumptions1. The length of the aluminum foil is14.79 cm. The thickness of the aluminum foil is0.02 mm3. The density of aluminum is $.71 \mathrm{~g/cm}^{3}$
4. The volume of the aluminum foil is $0.4 \mathrm{~cm}^{3}$
5. The width of the aluminum foil is not provided, but it is not needed for this problem because we are given the volume directly

STEP 2

We know that the mass of an object can be found by multiplying its volume by its density. We can write this as a formula $Mass = Volume \\times Density$

STEP 3

Now, plug in the given values for the volume and density to calculate the mass.
$Mass =0. \mathrm{~cm}^{3} \\times2.71 \mathrm{~g/cm}^{3}$

STEP 4

Calculate the mass of the aluminum foil.
$Mass =0.4 \mathrm{~cm}^{3} \\times2.71 \mathrm{~g/cm}^{3} =1.084 \mathrm{~g}$ The mass of the aluminum foil is1.084 grams.

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