QuestionCalculate the mean absolute deviation of these basketball player heights: 65, 62, 58, 63.

Studdy Solution

STEP 1

Assumptions1. The heights of the players are given in inches65,62,58,63. We need to find the mean absolute deviation (MAD)

STEP 2

First, we need to find the mean (average) of the heights. The mean is calculated by adding up all the numbers and then dividing by the total count of numbers.
$Mean = \frac{Sum\, of\, all\, numbers}{Total\, count\, of\, numbers}$

STEP 3

Now, plug in the given values for the heights to calculate the mean.
$Mean = \frac{65 +62 +58 +63}{}$

STEP 4

Calculate the mean height.
$Mean = \frac{248}{4} =62$

STEP 5

Next, we need to find the absolute deviations. The absolute deviation is the absolute value of the difference between each height and the mean.
$Absolute\, deviation = |height - mean|$

STEP 6

Now, plug in the given values for the heights and the mean to calculate the absolute deviations.
$Absolute\, deviations = |65 -62|, |62 -62|, |58 -62|, |63 -62|$

STEP 7

Calculate the absolute deviations.
$Absolute\, deviations =3,0,4,1$

STEP 8

Now, we need to find the mean of the absolute deviations. This is done by adding up all the absolute deviations and then dividing by the total count of numbers.
$Mean\, absolute\, deviation = \frac{Sum\, of\, absolute\, deviations}{Total\, count\, of\, numbers}$

STEP 9

Plug in the values for the sum of absolute deviations and the total count of numbers to calculate the mean absolute deviation.
$Mean\, absolute\, deviation = \frac{3 + +4 +}{4}$

STEP 10

Calculate the mean absolute deviation.
$Mean\, absolute\, deviation = \frac{8}{4} =2$ The mean absolute deviation of the heights of the players is2 inches.

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