Math  /  Geometry

QuestionFind the measures of the interior angles of the triangle A=\angle A= { }^{\circ} \square B=\angle B= \square C=\angle C=\square^{\circ}

Studdy Solution

STEP 1

1. We are given a triangle ABC \triangle ABC .
2. The measures of the angles are A=48 \angle A = 48^\circ , B=x \angle B = x^\circ , and C=(x44) \angle C = (x - 44)^\circ .
3. The sum of the interior angles of a triangle is 180 180^\circ .

STEP 2

1. Set up an equation using the sum of the interior angles of the triangle.
2. Solve the equation for x x .
3. Substitute the value of x x back into the expressions for B \angle B and C \angle C to find their measures.

STEP 3

Set up the equation using the sum of the interior angles of a triangle:
A+B+C=180 \angle A + \angle B + \angle C = 180^\circ
Substitute the given values:
48+x+(x44)=180 48^\circ + x^\circ + (x - 44)^\circ = 180^\circ

STEP 4

Simplify the equation:
48+x+x44=180 48 + x + x - 44 = 180
Combine like terms:
2x+4=180 2x + 4 = 180

STEP 5

Solve for x x :
Subtract 4 from both sides:
2x=176 2x = 176
Divide both sides by 2:
x=88 x = 88

STEP 6

Substitute x=88 x = 88 back into the expressions for B \angle B and C \angle C :
B=x=88 \angle B = x = 88^\circ
C=x44=8844=44 \angle C = x - 44 = 88 - 44 = 44^\circ
The measures of the interior angles of the triangle are:
A=48 \angle A = 48^\circ B=88 \angle B = 88^\circ C=44 \angle C = 44^\circ

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