Math

QuestionCalculate moles of ethanol needed for 0.085 mol of acetic acid from the reaction: C2H5OH+O2H2O+CH3COOH\mathrm{C_2H_5OH} + \mathrm{O_2} \rightarrow \mathrm{H_2O} + \mathrm{CH_3COOH}.

Studdy Solution

STEP 1

Assumptions1. The reaction between ethanol and oxygen gas produces water and acetic acid. . The reaction is balanced.
3. The moles of acetic acid produced is0.085 mol.

STEP 2

First, we need to write down the balanced chemical equation for the reaction. The balanced equation isCHCH2OH+2H2+CHCOOH\mathrm{CH}_{} \mathrm{CH}_{2} \mathrm{OH} + \mathrm{}_{2} \rightarrow \mathrm{H}_{2}\mathrm{} + \mathrm{CH}_{} \mathrm{COOH}

STEP 3

From the balanced chemical equation, we can see that one mole of ethanol reacts to produce one mole of acetic acid. This is a11 ratio.

STEP 4

Since the ratio of ethanol to acetic acid is11, the moles of ethanol needed to produce0.085 mol of acetic acid is also0.085 mol.
The solution is0.085 mol of ethanol.

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