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Math

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PROBLEM

Find the partial fraction decomposition of 53x+5412x223x+10\frac{-53x + 54}{12x^2 - 23x + 10}.
To set it up first write in the form A3x2+B4x5\frac{A}{3x - 2} + \frac{B}{4x - 5}
53x+5412x223x+10=  +  \frac{-53x + 54}{12x^2 - 23x + 10} = \frac{\text{ }}{\text{ }} + \frac{\text{ }}{\text{ }}
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STEP 1

What is this asking?
We need to break down a complicated fraction into simpler fractions.
Think of it like reversing the addition of fractions!
Watch out!
Don't forget to account for the denominators of the simpler fractions when putting them back together.

STEP 2

1. Factor the Denominator
2. Set up the Decomposition
3. Solve for the Unknowns
4. Verify the Decomposition

STEP 3

Alright, let's factor that denominator!
We're looking for two numbers that multiply to 1210=12012 \cdot 10 = 120 and add up to 23-23.
Those magic numbers are 8-8 and 15-15.

STEP 4

So, we rewrite the quadratic as 12x28x15x+1012x^2 - 8x - 15x + 10.
Now, we can factor by grouping.

STEP 5

From the first two terms, we can pull out 4x4x, giving us 4x(3x2)4x(3x - 2).
From the last two terms, we can pull out 5-5, giving us 5(3x2)-5(3x - 2).
Notice the common factor (3x2)(3x - 2)!

STEP 6

This means our factored denominator is (4x5)(3x2)(4x - 5)(3x - 2).
Boom!

STEP 7

Now, we can set up our partial fraction decomposition:
53x+54(4x5)(3x2)=A3x2+B4x5 \frac{-53x + 54}{(4x - 5)(3x - 2)} = \frac{A}{3x - 2} + \frac{B}{4x - 5} We're trying to find the mystery numbers AA and BB!

STEP 8

To solve for AA and BB, we'll multiply both sides of the equation by the denominator (4x5)(3x2)(4x - 5)(3x - 2).
This gives us:
53x+54=A(4x5)+B(3x2) -53x + 54 = A(4x - 5) + B(3x - 2)

STEP 9

Let's be clever!
If we set x=23x = \frac{2}{3}, the term with BB disappears!
5323+54=A(4235) -53 \cdot \frac{2}{3} + 54 = A(4 \cdot \frac{2}{3} - 5) 1063+1623=A(83153) \frac{-106}{3} + \frac{162}{3} = A(\frac{8}{3} - \frac{15}{3}) 563=A(73) \frac{56}{3} = A(\frac{-7}{3}) Multiplying both sides by 33 and dividing by 7-7 gives us A=567=8A = \frac{56}{-7} = -8.
Yes!

STEP 10

Now, let's set x=54x = \frac{5}{4} to make the term with AA vanish!
5354+54=B(3542) -53 \cdot \frac{5}{4} + 54 = B(3 \cdot \frac{5}{4} - 2) 2654+2164=B(15484) \frac{-265}{4} + \frac{216}{4} = B(\frac{15}{4} - \frac{8}{4}) 494=B(74) \frac{-49}{4} = B(\frac{7}{4}) Multiplying both sides by 44 and dividing by 77 gives us B=497=7B = \frac{-49}{7} = -7.
Awesome!

STEP 11

Let's verify our solution!
We found A=8A = -8 and B=7B = -7, so our decomposition is:
83x2+74x5 \frac{-8}{3x - 2} + \frac{-7}{4x - 5}

STEP 12

We can rewrite this as a single fraction by finding a common denominator:
8(4x5)7(3x2)(3x2)(4x5)=32x+4021x+1412x223x+10=53x+5412x223x+10 \frac{-8(4x - 5) - 7(3x - 2)}{(3x - 2)(4x - 5)} = \frac{-32x + 40 - 21x + 14}{12x^2 - 23x + 10} = \frac{-53x + 54}{12x^2 - 23x + 10} It matches the original expression!

SOLUTION

The partial fraction decomposition is:
83x274x5 \frac{-8}{3x - 2} - \frac{7}{4x - 5}

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