Math  /  Algebra

QuestionFind the partial sum of the geometric sequence given a=3,r=2a=3, r=2, n=8\mathrm{n}=8.

Studdy Solution

STEP 1

1. The sequence is geometric, meaning each term after the first is found by multiplying the previous term by a constant, called the common ratio r r .
2. The first term of the sequence is a=3 a = 3 .
3. The common ratio is r=2 r = 2 .
4. The number of terms to sum is n=8 n = 8 .

STEP 2

1. Identify the formula for the partial sum of a geometric sequence.
2. Substitute the given values into the formula.
3. Calculate the partial sum.

STEP 3

The formula for the partial sum Sn S_n of the first n n terms of a geometric sequence is:
Sn=arn1r1 S_n = a \frac{r^n - 1}{r - 1}
where a a is the first term, r r is the common ratio, and n n is the number of terms.

STEP 4

Substitute the given values a=3 a = 3 , r=2 r = 2 , and n=8 n = 8 into the formula:
S8=328121 S_8 = 3 \frac{2^8 - 1}{2 - 1}

STEP 5

Calculate the expression:
First, calculate 28 2^8 : 28=256 2^8 = 256
Next, substitute back into the formula: S8=325611 S_8 = 3 \frac{256 - 1}{1} S8=3×255 S_8 = 3 \times 255
Finally, calculate the product: S8=765 S_8 = 765
The partial sum of the geometric sequence is:
765 \boxed{765}

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