Math

QuestionFind the percent of the sum of the lowest two box tops collected compared to the highest two. Rooms: 600, 1000, 300, 800. Options: (A) 30%, (B) 50%, (C) 65%, (D) 70%, (E) 80%.

Studdy Solution

STEP 1

Assumptions1. Room100 collected600 box tops. Room159 collected1000 box tops3. Room206 collected300 box tops4. Room215 collected800 box tops

STEP 2

First, we need to find the sum of the box tops collected by the two rooms with the fewest box tops.

STEP 3

From the given data, we can see that the two rooms with the fewest box tops are Room100 and Room206.Fewestboxtops=Room100boxtops+Room206boxtopsFewest\, box\, tops = Room\,100\, box\, tops + Room\,206\, box\, tops

STEP 4

Plug in the values for Room100 and Room206 box tops to calculate the sum of the fewest box tops.
Fewestboxtops=600+300Fewest\, box\, tops =600 +300

STEP 5

Calculate the sum of the fewest box tops.
Fewestboxtops=600+300=900Fewest\, box\, tops =600 +300 =900

STEP 6

Next, we need to find the sum of the box tops collected by the two rooms with the most box tops.

STEP 7

From the given data, we can see that the two rooms with the most box tops are Room159 and Room215.Mostboxtops=Room159boxtops+Room215boxtopsMost\, box\, tops = Room\,159\, box\, tops + Room\,215\, box\, tops

STEP 8

Plug in the values for Room159 and Room215 box tops to calculate the sum of the most box tops.
Mostboxtops=1000+800Most\, box\, tops =1000 +800

STEP 9

Calculate the sum of the most box tops.
Mostboxtops=100+800=180Most\, box\, tops =100 +800 =180

STEP 10

Now that we have the sum of the fewest and most box tops, we can calculate the percentage of the fewest box tops to the most box tops.
Percentage=FewestboxtopsMostboxtops×100%Percentage = \frac{Fewest\, box\, tops}{Most\, box\, tops} \times100\%

STEP 11

Plug in the values for the fewest and most box tops to calculate the percentage.
Percentage=9001800×100%Percentage = \frac{900}{1800} \times100\%

STEP 12

Calculate the percentage.
Percentage=9001800×100%=50%Percentage = \frac{900}{1800} \times100\% =50\%The sum of the box tops collected by the two rooms with the fewest box tops is approximately50% of the sum of the box tops collected by the two rooms with the most box tops. So, the correct option is (B) 50%50 \%.

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