Math Snap

STEP 1

Assumptions1. The hydronium ion concentration is $1 \times10^{-11} M$.
. The pH of a solution is calculated using the formula $pH = -\log[H3^+]$, where $[H3^+]$ is the hydronium ion concentration.
3. The logarithm is base10.

STEP 2

We need to calculate the pH of the solution using the given hydronium ion concentration. We can do this by plugging the given concentration into the formula for pH.
$$pH = -\log[H^+]$$

STEP 3

Now, plug in the given value for the hydronium ion concentration to calculate the pH.
$$pH = -\log[1 \times10^{-11} M]$$

STEP 4

The logarithm of a product can be written as the sum of the logarithms of the individual numbers. So, we can rewrite the logarithm in the formula as follows$$pH = -(\log[1] + \log[10^{-11}])$$

STEP 5

The logarithm of1 is0, and the logarithm of $10^{-11}$ is -11. So, we can simplify the formula as follows$$pH = -(0 + -11)$$

Calculate the pH of the solution.
$$pH = -(-11) =11$$The pH of the solution is11.