Math

QuestionFind the range of the function f(x)={0if x4xif 4<x<0x2if x0f(x) = \begin{cases} 0 & \text{if } x \leq -4 \\ -x & \text{if } -4 < x < 0 \\ x^2 & \text{if } x \geq 0 \end{cases}.

Studdy Solution

STEP 1

Assumptions1. The function is piece-wise defined with three parts 00 for x4x \leq -4, x-x for 4x<0-4 \leq x <0, and xx^{} for x0x \geq0.

STEP 2

First, we need to determine the range of each piece of the function separately.For x4x \leq -4, the function is constant at 00. So, the range for this part is just 00.

STEP 3

For x<0- \leq x <0, the function is x-x. As xx increases from - to 00, x-x decreases from $$ to $0$. So, the range for this part is $[0,)$.

STEP 4

For x0x \geq0, the function is x2x^{2}. As xx increases from 00 to \infty, x2x^{2} also increases from 00 to \infty. So, the range for this part is [0,)[0, \infty).

STEP 5

Now, we combine the ranges of all the pieces to get the range of the entire function.
The range of the function f(x)f(x) is the set of all possible values of f(x)f(x), which is the union of the ranges of all the pieces.
So, the range of f(x)f(x) is [0,)[0, \infty).

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