Math

QuestionFind the reference angle for θ=26π7\theta = -\frac{26 \pi}{7}. What is the least nonnegative coterminal angle θC\theta_{C}? In which quadrant is θC\theta_{C}?

Studdy Solution

STEP 1

Assumptions1. The given angle is θ=26π7\theta=-\frac{26 \pi}{7} . The reference angle is the acute angle that the terminal side of the angle makes with the x-axis3. The angle of least nonnegative measure coterminal with θ\theta is θC=π7\theta_{C}=\frac{ \pi}{7}
4. The terminal side of θC\theta_{C} lies in a certain quadrant, which we need to determine

STEP 2

First, we need to find the reference angle for θ=26π7\theta=-\frac{26 \pi}{7}. The reference angle is always positive and less than or equal to π2\frac{\pi}{2}. We can find it by taking the absolute value of θ\theta and then subtracting the largest multiple of π\pi that is less than or equal to the absolute value.
θR=θnπ\theta_{R} = |\theta| - n\piwhere nn is the largest integer such that nπθn\pi \leq |\theta|.

STEP 3

Now, plug in the given value for θ\theta to calculate the reference angle.
θR=26π7nπ\theta_{R} = |-\frac{26 \pi}{7}| - n\pi

STEP 4

Calculate the absolute value of θ\theta.
θR=26π7nπ\theta_{R} = \frac{26 \pi}{7} - n\pi

STEP 5

We can see that n=3n=3 is the largest integer such that nπ26π7n\pi \leq \frac{26 \pi}{7}, so we substitute n=3n=3 into the equation.
θR=26π73π\theta_{R} = \frac{26 \pi}{7} -3\pi

STEP 6

Calculate the reference angle.
θR=26π3π=5π\theta_{R} = \frac{26 \pi}{} -3\pi = \frac{5 \pi}{}

STEP 7

Now, we need to find the angle of least nonnegative measure coterminal with θ\theta. This is the smallest positive angle that has the same terminal side as θ\theta. We can find it by adding multiples of 2π2\pi to θ\theta until we get a positive angle.
θC=θ+2nπ\theta_{C} = \theta +2n\piwhere nn is the smallest integer such that θC>0\theta_{C} >0.

STEP 8

We are given that θC=2π7\theta_{C}=\frac{2 \pi}{7}, so we don't need to calculate it.

STEP 9

Finally, we need to determine in what quadrant the terminal side of θC\theta_{C} lies. We know that θC=2π7\theta_{C}=\frac{2 \pi}{7}, which is less than π2\frac{\pi}{2}, so the terminal side of θC\theta_{C} lies in the first quadrant.
The reference angle for θ=26π7\theta=-\frac{26 \pi}{7} is 5π7\frac{5 \pi}{7}, the angle of least nonnegative measure coterminal with θ\theta is 2π7\frac{2 \pi}{7}, and the terminal side of θC\theta_{C} lies in the first quadrant.

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