QuestionFind the missing probability $p(2) = C$ in the distribution: $p(0)=0.1$ , $p(1)=0.3$ , $p(3)=0.2$ .

Studdy Solution

STEP 1

Assumptions1. The given values are part of a discrete probability distribution. . In a discrete probability distribution, the sum of all probabilities is equal to1.

STEP 2

We first need to find the sum of the given probabilities.
$Sum\, of\, given\, probabilities = p(0) + p(1) + p()$

STEP 3

Now, plug in the given values for the probabilities to calculate the sum.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2$

STEP 4

Calculate the sum of the given probabilities.
$Sum\, of\, given\, probabilities =0.1 +0.3 +0.2 =0.6$

STEP 5

Now that we have the sum of the given probabilities, we can find the missing probability, $p(2)$ , by subtracting the sum of the given probabilities from1.
$p(2) =1 - Sum\, of\, given\, probabilities$

STEP 6

Plug in the value for the sum of the given probabilities to calculate the missing probability.
$p(2) =1 -0.6$

STEP 7

Calculate the missing probability.
$p(2) =1 -0.6 =0.4$ The missing probability, $p(2)$ , is0.4.

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