QuestionCalculate $\frac{10 j}{7 v}$ given $10 j^{2}+2 j v-55 j h-11 v h=0$ and $j \neq \frac{11}{2} h$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $10 j^{}+ j v-55 j h-11 v h=0$ . $j \neq \frac{11}{} h$
3. We need to find the value of $\frac{10 j}{7 v}$

STEP 2

We can rewrite the given equation in terms of $j$ as follows $j(10j +2v -55h) =11vh$

STEP 3

Now, we can solve for $j$ $j = \frac{11vh}{10j +2v -55h}$

STEP 4

We are given that $j \neq \frac{11}{2} h$ . So, we can simplify the denominator $j = \frac{11vh}{2v -h}$

STEP 5

Now, we can substitute this value of $j$ into the expression $\frac{10 j}{7 v}$ $\frac{10 j}{7 v} = \frac{10 \times \frac{11vh}{2v -5h}}{7v}$

STEP 6

implify the expression $\frac{10 j}{ v} = \frac{110vh}{v(2v -5h)}$

STEP 7

Cancel out the common factor of $v$ from the numerator and the denominator $\frac{10 j}{7 v} = \frac{110h}{7(2v -5h)}$ So, the value of $\frac{10 j}{7 v}$ is $\frac{110h}{7(2v -5h)}$ .

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QuestionCalculate $\frac{10 j}{7 v}$ given $10 j^{2}+2 j v-55 j h-11 v h=0$ and $j \neq \frac{11}{2} h$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $10 j^{}+ j v-55 j h-11 v h=0$ . $j \neq \frac{11}{} h$
3. We need to find the value of $\frac{10 j}{7 v}$

STEP 2

We can rewrite the given equation in terms of $j$ as follows $j(10j +2v -55h) =11vh$

STEP 3

Now, we can solve for $j$ $j = \frac{11vh}{10j +2v -55h}$

STEP 4

We are given that $j \neq \frac{11}{2} h$ . So, we can simplify the denominator $j = \frac{11vh}{2v -h}$

STEP 5

Now, we can substitute this value of $j$ into the expression $\frac{10 j}{7 v}$ $\frac{10 j}{7 v} = \frac{10 \times \frac{11vh}{2v -5h}}{7v}$

STEP 6

implify the expression $\frac{10 j}{ v} = \frac{110vh}{v(2v -5h)}$

STEP 7

Cancel out the common factor of $v$ from the numerator and the denominator $\frac{10 j}{7 v} = \frac{110h}{7(2v -5h)}$ So, the value of $\frac{10 j}{7 v}$ is $\frac{110h}{7(2v -5h)}$ .

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QuestionCalculate 10j7v\frac{10 j}{7 v}7v10j​ given 10j2+2jv−55jh−11vh=010 j^{2}+2 j v-55 j h-11 v h=010j2+2jv−55jh−11vh=0 and j≠112hj \neq \frac{11}{2} hj=211​h.

Studdy Solution

STEP 1

Assumptions1. The equation given is 10j+jv−55jh−11vh=010 j^{}+ j v-55 j h-11 v h=010j+jv−55jh−11vh=0 . j≠11hj \neq \frac{11}{} hj=11​h3. We need to find the value of 10j7v\frac{10 j}{7 v}7v10j​

STEP 2

We can rewrite the given equation in terms of jjj as followsj(10j+2v−55h)=11vhj(10j +2v -55h) =11vhj(10j+2v−55h)=11vh

STEP 3

Now, we can solve for jjjj=11vh10j+2v−55hj = \frac{11vh}{10j +2v -55h}j=10j+2v−55h11vh​

STEP 4

We are given that j≠112hj \neq \frac{11}{2} hj=211​h. So, we can simplify the denominatorj=11vh2v−hj = \frac{11vh}{2v -h}j=2v−h11vh​

STEP 5

Now, we can substitute this value of jjj into the expression 10j7v\frac{10 j}{7 v}7v10j​10j7v=10×11vh2v−5h7v\frac{10 j}{7 v} = \frac{10 \times \frac{11vh}{2v -5h}}{7v}7v10j​=7v10×2v−5h11vh​​

STEP 6

implify the expression10jv=110vhv(2v−5h)\frac{10 j}{ v} = \frac{110vh}{v(2v -5h)}v10j​=v(2v−5h)110vh​

STEP 7

Cancel out the common factor of vvv from the numerator and the denominator10j7v=110h7(2v−5h)\frac{10 j}{7 v} = \frac{110h}{7(2v -5h)}7v10j​=7(2v−5h)110h​So, the value of 10j7v\frac{10 j}{7 v}7v10j​ is 110h7(2v−5h)\frac{110h}{7(2v -5h)}7(2v−5h)110h​.

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QuestionCalculate $\frac{10 j}{7 v}$ given $10 j^{2}+2 j v-55 j h-11 v h=0$ and $j \neq \frac{11}{2} h$ .

Assumptions1. The equation given is $10 j^{}+ j v-55 j h-11 v h=0$ . $j \neq \frac{11}{} h$
3. We need to find the value of $\frac{10 j}{7 v}$

We can rewrite the given equation in terms of $j$ as follows $j(10j +2v -55h) =11vh$

Now, we can solve for $j$ $j = \frac{11vh}{10j +2v -55h}$

We are given that $j \neq \frac{11}{2} h$ . So, we can simplify the denominator $j = \frac{11vh}{2v -h}$

Now, we can substitute this value of $j$ into the expression $\frac{10 j}{7 v}$ $\frac{10 j}{7 v} = \frac{10 \times \frac{11vh}{2v -5h}}{7v}$

implify the expression $\frac{10 j}{ v} = \frac{110vh}{v(2v -5h)}$

Cancel out the common factor of $v$ from the numerator and the denominator $\frac{10 j}{7 v} = \frac{110h}{7(2v -5h)}$ So, the value of $\frac{10 j}{7 v}$ is $\frac{110h}{7(2v -5h)}$ .