Math

QuestionFind f(g(h(3)))f(g(h(3))) for f(x)=2x3f(x)=-2 x^{3}, g(x)=3x5g(x)=3 x-5, and h(x)=x1h(x)=x-1. Options: 129-129, 54-54, 53-53, 2-2.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is given by f(x)=x3f(x)=- x^{3} . The function (x)(x) is given by g(x)=3x5g(x)=3 x-5
3. The function h(x)h(x) asked to find the value of f(g(h(3)))f(g(h(3)))

STEP 2

First, we need to find the value of h()h(). We can do this by substituting x=x= into the function h(x)h(x).
h()=1h() = -1

STEP 3

Calculate the value of h(3)h(3).
h(3)=31=2h(3) =3 -1 =2

STEP 4

Now that we have the value of h(3)h(3), we can find the value of g(h(3))g(h(3)). We do this by substituting x=h(3)x=h(3) into the function g(x)g(x).
g(h(3))=g(2)=32g(h(3)) = g(2) =3 \cdot2 -

STEP 5

Calculate the value of g(h(3))g(h(3)).
g(h(3))=325=1g(h(3)) =3 \cdot2 -5 =1

STEP 6

Now that we have the value of g(h(3))g(h(3)), we can find the value of f(g(h(3)))f(g(h(3))). We do this by substituting x=g(h(3))x=g(h(3)) into the function f(x)f(x).
f(g(h(3)))=f(1)=213f(g(h(3))) = f(1) = -2 \cdot1^{3}

STEP 7

Calculate the value of f(g(h(3)))f(g(h(3))).
f(g(h(3)))=213=2f(g(h(3))) = -2 \cdot1^{3} = -2So, f(g(h(3)))=2f(g(h(3))) = -2.

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