Math

QuestionCari nilai hh bagi 5log3(h3)+log3h=65 \log _{3}\left(\frac{h}{3}\right)+\log _{3} \sqrt{h}=6.

Studdy Solution

STEP 1

Assumptions1. We are given the equation 5log3(h3)+log3h=65 \log{3}\left(\frac{h}{3}\right)+\log{3} \sqrt{h}=6. . We need to find the value of hh that satisfies this equation.
3. We assume that h>0h >0 because the argument of a logarithm and the radicand of a square root must be positive.

STEP 2

First, let's simplify the equation by using the properties of logarithms. We can start by applying the power rule of logarithms to the first term on the left-hand side. The power rule states that alogbc=logb(ca)a \log_b c = \log_b (c^a).
5log(h)=log((h)5)5 \log{}\left(\frac{h}{}\right) = \log{}\left(\left(\frac{h}{}\right)^5\right)

STEP 3

Now, apply the power rule to the second term on the left-hand side. The power rule states that logbc=12logbc\log_b \sqrt{c} = \frac{1}{2} \log_b c.
log3h=12log3h\log{3} \sqrt{h} = \frac{1}{2} \log{3} h

STEP 4

Substitute the simplified terms back into the original equation.
\log{3}\left(\left(\frac{h}{3}\right)^\right) + \frac{1}{2} \log{3} h =6

STEP 5

We can further simplify the equation by combining the logarithms on the left-hand side into a single logarithm. The product rule of logarithms states that logba+logbc=logb(ac)\log_b a + \log_b c = \log_b (a \cdot c).
log3((h3)5h1/2)=\log{3}\left(\left(\frac{h}{3}\right)^5 \cdot h^{1/2}\right) =

STEP 6

Next, we can eliminate the logarithm by raising both sides of the equation to the base of the logarithm, which is3. This gives us(h3)5h1/2=36\left(\frac{h}{3}\right)^5 \cdot h^{1/2} =3^6

STEP 7

implify the right-hand side of the equation.
(h3)5h1/2=729\left(\frac{h}{3}\right)^5 \cdot h^{1/2} =729

STEP 8

Now, rewrite the left-hand side of the equation to make it easier to solve for hh.
h535h1/2=729\frac{h^5}{3^5} \cdot h^{1/2} =729

STEP 9

Multiply both sides of the equation by 353^5 to get rid of the denominator on the left-hand side.
h5h/2=72935h^5 \cdot h^{/2} =729 \cdot3^5

STEP 10

implify the right-hand side of the equation.
h5h/2=59049h^5 \cdot h^{/2} =59049

STEP 11

Combine the powers of hh on the left-hand side of the equation.
h5+/=59049h^{5 +/} =59049

STEP 12

implify the exponent on the left-hand side of the equation.
h11/2=59049h^{11/2} =59049

STEP 13

To solve for hh, raise both sides of the equation to the power of 2/112/11.
h=(59049)2/11h = (59049)^{2/11}

STEP 14

Calculate the value of hh.
h=9h =9The value of hh that satisfies the given equation is9.

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