Math

QuestionFind (fg)(4)(f-g)(4) where f(x)=4x3f(x)=4x-3 and g(x)=x3+2xg(x)=x^3+2x.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is given by f(x)=4x3f(x) =4x -3 . The function g(x)g(x) is given by g(x)=x3+xg(x) = x^3 +x
3. We are asked to find the value of (fg)(4)(f - g)(4), which means we need to subtract the value of function gg at x=4x =4 from the value of function ff at x=4x =4

STEP 2

First, we need to find the value of f(4)f(4). We can do this by substituting x=4x =4 into the function f(x)f(x).
f(4)=4(4)f(4) =4(4) -

STEP 3

Now, calculate the value of f()f().
f()=()3=163=13f() =() -3 =16 -3 =13

STEP 4

Next, we need to find the value of g(4)g(4). We can do this by substituting x=4x =4 into the function g(x)g(x).
g(4)=(4)3+2(4)g(4) = (4)^3 +2(4)

STEP 5

Now, calculate the value of g(4)g(4).
g(4)=(4)3+2(4)=64+8=72g(4) = (4)^3 +2(4) =64 +8 =72

STEP 6

Now that we have the values of f(4)f(4) and g(4)g(4), we can find the value of (fg)(4)(f - g)(4) by subtracting the value of g(4)g(4) from the value of f(4)f(4).
(fg)(4)=f(4)g(4)(f - g)(4) = f(4) - g(4)

STEP 7

Plug in the values for f(4)f(4) and g(4)g(4) to calculate (fg)(4)(f - g)(4).
(fg)(4)=1372(f - g)(4) =13 -72

STEP 8

Calculate the value of (fg)(4)(f - g)(4).
(fg)(4)=1372=59(f - g)(4) =13 -72 = -59So, (fg)(4)=59(f - g)(4) = -59.

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