Math

QuestionFind the value of the function f(x)=3x2+10x+2f(x)=-3 x^{2}+10 x+2 at x=6x=-6. What is f(6)f(-6)?

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=3x+10x+f(x)=-3 x^{}+10 x+ . We need to find the value of f(6)f(-6)

STEP 2

To find the value of f(6)f(-6), we need to substitute 6-6 for xx in the function.
f(6)=(6)2+10(6)+2f(-6) = -(-6)^{2}+10(-6)+2

STEP 3

First, calculate the value of (6)2(-6)^{2}.
(6)2=36(-6)^{2} =36

STEP 4

Substitute 3636 for (6)2(-6)^{2} in the function.
f(6)=3(36)+10(6)+2f(-6) = -3(36)+10(-6)+2

STEP 5

Calculate the value of 3(36)-3(36).
3(36)=108-3(36) = -108

STEP 6

Substitute 108-108 for 3(36)-3(36) in the function.
f(6)=108+10(6)+2f(-6) = -108+10(-6)+2

STEP 7

Calculate the value of 10(6)10(-6).
10(6)=6010(-6) = -60

STEP 8

Substitute 60-60 for 10(6)10(-6) in the function.
f(6)=10860+2f(-6) = -108-60+2

STEP 9

Calculate the value of 10860+2-108-60+2.
10860+2=166-108-60+2 = -166So, f(6)=166f(-6) = -166.

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