Math  /  Geometry

QuestionFind the value of xx that makes mnm \| n.
DOL:

Studdy Solution

STEP 1

What is this asking? We need to find the value of xx that makes lines mm and nn parallel, given two angles formed by a line crossing them. Watch out! Remember, there are *multiple* angle relationships when lines are crossed by another line, so make sure you pick the right one!

STEP 2

1. Set up the equation
2. Solve for xx

STEP 3

Hey everyone!
Notice that the angles measuring 3x3x^\circ and (x+20)(x + 20)^\circ are *corresponding angles*.
If lines mm and nn are parallel, corresponding angles are *equal*!

STEP 4

So, we can **set up** the equation: 3x=x+203x = x + 20 This equation says that if the angles are equal, then the lines are parallel.

STEP 5

Let's **isolate** xx by subtracting xx from both sides of the equation.
Remember, what we do on one side, we *must* do to the other! 3xx=x+20x3x - x = x + 20 - x 2x=202x = 20We subtracted xx to move all the xx terms to one side, making it easier to solve!

STEP 6

Now, let's **divide** both sides by 22 to get xx all by itself: 2x2=202 \frac{2x}{2} = \frac{20}{2} x=10 x = 10 We divide by 2\bf{2} because 2\bf{2} multiplied by xx is 2x2x, and we want to find the value of just one xx.
Dividing by 22 gets us there!

STEP 7

Therefore, the value of xx that makes mnm \parallel n is 10\bf{10}.

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