QuestionSolve for $y$ in the equation $3x - 4y = \pm20$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x -4y = \pm20$ . We are solving for $y$
3. The symbol $\pm$ means that we will have two solutions, one for $+20$ and one for $-20$

STEP 2

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

STEP 3

implify the equation.
$-y = \pm20 -3x$

STEP 4

Next, we need to get rid of the $-4$ coefficient on $y$ . We can do this by dividing every term by $-4$ .
$\frac{-4y}{-4} = \frac{\pm20 -3x}{-4}$

STEP 5

implify the equation.
$y = \frac{-\pm20 +3x}{4}$

STEP 6

Now, we can split the equation into two separate equations, one for $+20$ and one for $-20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$

STEP 7

Now we have the solutions for $y$ in terms of $x$ for the equation $3x -4y = \pm20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$

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QuestionSolve for $y$ in the equation $3x - 4y = \pm20$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x -4y = \pm20$ . We are solving for $y$
3. The symbol $\pm$ means that we will have two solutions, one for $+20$ and one for $-20$

STEP 2

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

STEP 3

implify the equation.
$-y = \pm20 -3x$

STEP 4

Next, we need to get rid of the $-4$ coefficient on $y$ . We can do this by dividing every term by $-4$ .
$\frac{-4y}{-4} = \frac{\pm20 -3x}{-4}$

STEP 5

implify the equation.
$y = \frac{-\pm20 +3x}{4}$

STEP 6

Now, we can split the equation into two separate equations, one for $+20$ and one for $-20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$

STEP 7

Now we have the solutions for $y$ in terms of $x$ for the equation $3x -4y = \pm20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$

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QuestionSolve for yyy in the equation 3x−4y=±203x - 4y = \pm203x−4y=±20.

Studdy Solution

STEP 1

Assumptions1. The equation is 3x−4y=±203x -4y = \pm203x−4y=±20 . We are solving for yyy3. The symbol ±\pm± means that we will have two solutions, one for +20+20+20 and one for −20-20−20

STEP 2

First, we need to isolate yyy in the equation. We can do this by subtracting xxx from both sides of the equation.x−4y−x=±20−xx -4y -x = \pm20 -xx−4y−x=±20−x

STEP 3

implify the equation.−y=±20−3x-y = \pm20 -3x−y=±20−3x

STEP 4

Next, we need to get rid of the −4-4−4 coefficient on yyy. We can do this by dividing every term by −4-4−4.−4y−4=±20−3x−4\frac{-4y}{-4} = \frac{\pm20 -3x}{-4}−4−4y​=−4±20−3x​

STEP 5

implify the equation.y=−±20+3x4y = \frac{-\pm20 +3x}{4}y=4−±20+3x​

STEP 6

Now, we can split the equation into two separate equations, one for +20+20+20 and one for −20-20−20.For +20+20+20y=−20+3x4y = \frac{-20 +3x}{4}y=4−20+3x​For −20-20−20y=20+3x4y = \frac{20 +3x}{4}y=420+3x​

STEP 7

Now we have the solutions for yyy in terms of xxx for the equation 3x−4y=±203x -4y = \pm203x−4y=±20.For +20+20+20y=−20+3x4y = \frac{-20 +3x}{4}y=4−20+3x​For −20-20−20y=20+3x4y = \frac{20 +3x}{4}y=420+3x​

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QuestionSolve for $y$ in the equation $3x - 4y = \pm20$ .

Assumptions1. The equation is $3x -4y = \pm20$ . We are solving for $y$
3. The symbol $\pm$ means that we will have two solutions, one for $+20$ and one for $-20$

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

implify the equation.
$-y = \pm20 -3x$

Next, we need to get rid of the $-4$ coefficient on $y$ . We can do this by dividing every term by $-4$ .
$\frac{-4y}{-4} = \frac{\pm20 -3x}{-4}$

implify the equation.
$y = \frac{-\pm20 +3x}{4}$

Now, we can split the equation into two separate equations, one for $+20$ and one for $-20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$

Now we have the solutions for $y$ in terms of $x$ for the equation $3x -4y = \pm20$ .
For $+20$ $y = \frac{-20 +3x}{4}$ For $-20$ $y = \frac{20 +3x}{4}$