Math  /  Algebra

QuestionFind the vertical asymptotes (VA) and horizontal asymptotes (HA) of the rational function y=x2+4x+32x2+5x7 y = \frac{x^2 + 4x + 3}{2x^2 + 5x - 7} .

Studdy Solution

STEP 1

1. A vertical asymptote occurs where the denominator of a rational function equals zero, provided the numerator is not zero at those points.
2. A horizontal asymptote is determined by comparing the degrees of the numerator and the denominator.

STEP 2

1. Find the vertical asymptotes by solving for when the denominator equals zero.
2. Determine if there are horizontal asymptotes by comparing the degrees of the numerator and denominator.

STEP 3

To find the vertical asymptotes, set the denominator equal to zero and solve for x x :
2x2+5x7=0 2x^2 + 5x - 7 = 0

STEP 4

Solve the quadratic equation 2x2+5x7=0 2x^2 + 5x - 7 = 0 using the quadratic formula:
The quadratic formula is given by:
x=b±b24ac2a x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
where a=2 a = 2 , b=5 b = 5 , and c=7 c = -7 .

STEP 5

Calculate the discriminant b24ac b^2 - 4ac :
b24ac=5242(7) b^2 - 4ac = 5^2 - 4 \cdot 2 \cdot (-7) =25+56 = 25 + 56 =81 = 81

STEP 6

Substitute the values into the quadratic formula:
x=5±814 x = \frac{-5 \pm \sqrt{81}}{4} x=5±94 x = \frac{-5 \pm 9}{4}
Calculate the two possible solutions:
x=5+94=1 x = \frac{-5 + 9}{4} = 1 x=594=144=72 x = \frac{-5 - 9}{4} = -\frac{14}{4} = -\frac{7}{2}
The vertical asymptotes are x=1 x = 1 and x=72 x = -\frac{7}{2} .

STEP 7

To find the horizontal asymptotes, compare the degrees of the numerator and denominator:
The degree of the numerator x2+4x+3 x^2 + 4x + 3 is 2. The degree of the denominator 2x2+5x7 2x^2 + 5x - 7 is 2.
Since the degrees are equal, the horizontal asymptote is determined by the ratio of the leading coefficients.

STEP 8

The leading coefficient of the numerator is 1, and the leading coefficient of the denominator is 2. Therefore, the horizontal asymptote is:
y=12 y = \frac{1}{2}
The vertical asymptotes are x=1 x = 1 and x=72 x = -\frac{7}{2} , and the horizontal asymptote is y=12 y = \frac{1}{2} .

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