QuestionFind three consecutive integers that add up to 339. Let the smallest be $n$ , then the integers are $n$ , $n+1$ , and $n+2$ .

Studdy Solution

STEP 1

Assumptions1. Let $n$ represent the smallest of the three integers. . The other two numbers are $n+1$ and $n+$ .
3. The sum of these three consecutive integers is339.

STEP 2

We can express the sum of the three consecutive integers as an equation.
$n + (n+1) + (n+2) =339$

STEP 3

implify the left side of the equation by combining like terms.
$3n +3 =339$

STEP 4

Subtract3 from both sides of the equation to isolate the term with $n$ .
$3n =339 -3$

STEP 5

Calculate the right side of the equation.
$3n =336$

STEP 6

Divide both sides of the equation by3 to solve for $n$ .
$n =336 /3$

STEP 7

Calculate the value of $n$ .
$n =112$

STEP 8

Now that we have the smallest integer, we can find the other two by adding1 and2 to $n$ .
$n+1 =112 +1$ $n+2 =112 +2$

STEP 9

Calculate the values of $n+$ and $n+2$ .
$n+ =113$ $n+2 =114$ The three consecutive integers are112,113, and114.

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QuestionFind three consecutive integers that add up to 339. Let the smallest be $n$ , then the integers are $n$ , $n+1$ , and $n+2$ .

Studdy Solution

STEP 1

Assumptions1. Let $n$ represent the smallest of the three integers. . The other two numbers are $n+1$ and $n+$ .
3. The sum of these three consecutive integers is339.

STEP 2

We can express the sum of the three consecutive integers as an equation.
$n + (n+1) + (n+2) =339$

STEP 3

implify the left side of the equation by combining like terms.
$3n +3 =339$

STEP 4

Subtract3 from both sides of the equation to isolate the term with $n$ .
$3n =339 -3$

STEP 5

Calculate the right side of the equation.
$3n =336$

STEP 6

Divide both sides of the equation by3 to solve for $n$ .
$n =336 /3$

STEP 7

Calculate the value of $n$ .
$n =112$

STEP 8

Now that we have the smallest integer, we can find the other two by adding1 and2 to $n$ .
$n+1 =112 +1$ $n+2 =112 +2$

STEP 9

Calculate the values of $n+$ and $n+2$ .
$n+ =113$ $n+2 =114$ The three consecutive integers are112,113, and114.

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QuestionFind three consecutive integers that add up to 339. Let the smallest be nnn, then the integers are nnn, n+1n+1n+1, and n+2n+2n+2.

Studdy Solution

STEP 1

Assumptions1. Let nnn represent the smallest of the three integers. . The other two numbers are n+1n+1n+1 and n+n+n+.3. The sum of these three consecutive integers is339.

STEP 2

We can express the sum of the three consecutive integers as an equation.n+(n+1)+(n+2)=339n + (n+1) + (n+2) =339n+(n+1)+(n+2)=339

STEP 3

implify the left side of the equation by combining like terms.3n+3=3393n +3 =3393n+3=339

STEP 4

Subtract3 from both sides of the equation to isolate the term with nnn.3n=339−33n =339 -33n=339−3

STEP 5

Calculate the right side of the equation.3n=3363n =3363n=336

STEP 6

Divide both sides of the equation by3 to solve for nnn.n=336/3n =336 /3n=336/3

STEP 7

Calculate the value of nnn.n=112n =112n=112

STEP 8

Now that we have the smallest integer, we can find the other two by adding1 and2 to nnn.n+1=112+1n+1 =112 +1n+1=112+1n+2=112+2n+2 =112 +2n+2=112+2

STEP 9

Calculate the values of n+n+n+ and n+2n+2n+2.n+=113n+ =113n+=113n+2=114n+2 =114n+2=114The three consecutive integers are112,113, and114.

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Studdy solves anything!

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind three consecutive integers that add up to 339. Let the smallest be $n$ , then the integers are $n$ , $n+1$ , and $n+2$ .

Assumptions1. Let $n$ represent the smallest of the three integers. . The other two numbers are $n+1$ and $n+$ .
3. The sum of these three consecutive integers is339.

We can express the sum of the three consecutive integers as an equation.
$n + (n+1) + (n+2) =339$

implify the left side of the equation by combining like terms.
$3n +3 =339$

Subtract3 from both sides of the equation to isolate the term with $n$ .
$3n =339 -3$

Calculate the right side of the equation.
$3n =336$

Divide both sides of the equation by3 to solve for $n$ .
$n =336 /3$

Calculate the value of $n$ .
$n =112$

Now that we have the smallest integer, we can find the other two by adding1 and2 to $n$ .
$n+1 =112 +1$ $n+2 =112 +2$

Calculate the values of $n+$ and $n+2$ .
$n+ =113$ $n+2 =114$ The three consecutive integers are112,113, and114.