QuestionFind three consecutive even integers where the sum of the smallest and middle equals 44 more than the largest.
Studdy Solution
STEP 1
Assumptions1. We are looking for three consecutive even integers. . The sum of the least integer and the middle integer is44 more than the greatest integer.
STEP 2
Let's denote the three consecutive even integers as x, x+2, and x+4. This is because even integers are always2 units apart.
STEP 3
According to the problem, the sum of the least integer and the middle integer is44 more than the greatest integer. We can write this as an equation
STEP 4
implify the equation by combining like terms on both sides.
STEP 5
Subtract x from both sides of the equation to isolate the variable on one side.
STEP 6
implify the equation.
STEP 7
Now that we have the value for x, we can find the three consecutive even integers.The least integer is x, the middle integer is x+2, and the greatest integer is x+4.
STEP 8
Substitute the value of x into the expressions for the three integers.
Least integer = x =46Middle integer = x+2 =46+2Greatest integer = x+4 =46+4
STEP 9
Calculate the values of the middle and greatest integers.
Middle integer =46+2 =48Greatest integer =46+4 =50The three consecutive even integers are46,48, and50.
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