Math

QuestionFind two whole numbers nn and mm such that n2<31<m2n^2 < 31 < m^2. What are these numbers?

Studdy Solution

STEP 1

Assumptions1. We are looking for two whole numbers such that one of them squared is less than31 and the other squared is more than31.. The user is not familiar with the concept of square roots and squaring numbers.

STEP 2

Let's start by explaining what squaring a number means. When we square a number, we multiply it by itself. For example, if we square the number2, we get 22=2×2=42^2 =2 \times2 =4.
22=2×2=42^2 =2 \times2 =4

STEP 3

Similarly, if we square the number3, we get 32=3×3=93^2 =3 \times3 =9.
32=3×3=93^2 =3 \times3 =9

STEP 4

Let's continue this process with larger numbers. If we square the number4, we get 42=4×4=164^2 =4 \times4 =16.
42=4×4=164^2 =4 \times4 =16

STEP 5

If we square the number5, we get 52=5×5=255^2 =5 \times5 =25.
52=5×5=255^2 =5 \times5 =25

STEP 6

If we square the number6, we get 62=6×6=366^2 =6 \times6 =36.
62=6×6=366^2 =6 \times6 =36

STEP 7

Now, let's look at the numbers we have squared so far. We see that 52=255^2 =25 is less than31 and 62=366^2 =36 is more than31.

STEP 8

So, the two consecutive whole numbers between which 31\sqrt{31} lies are5 and6.
The square root of31 is between5 and6.

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