Math  /  Calculus

QuestionFirst-class postage is $0.34\$ 0.34 for the first ounce (or any fraction thereof) and $0.25\$ 0.25 for each additional ounce (or fraction thereof). Let C(x)C(x) represent the postage for a letter weighing ×\times oz. Use this information to answer the questions. a) Find limC(x)\lim C(x). Select the correct choice below and fill in any answer boxes in your choice. x3x \rightarrow 3^{-} A. limx3C(x)=$\lim _{x \rightarrow 3^{-}} C(x)=\$ \square (Type an integer or a decimal.) \square B. The limit does not exist.

Studdy Solution

STEP 1

1. The cost function C(x)C(x) is defined piecewise based on the weight xx of the letter in ounces.
2. The cost is \0.34forthefirstounceoranyfractionthereof.<br/>3.Foreachadditionalounceorfractionthereof,thecostisanadditional$0.25perounce.<br/>4.Weneedtoevaluatethelimit0.34 for the first ounce or any fraction thereof.<br />3. For each additional ounce or fraction thereof, the cost is an additional \$0.25 per ounce.<br />4. We need to evaluate the limit \lim_{x \rightarrow 3^{-}} C(x),where, where x$ is approaching 3 from the left.

STEP 2

1. Define the cost function C(x)C(x) based on the given pricing structure.
2. Determine the cost for weights approaching 3 ounces from the left.
3. Evaluate the limit limx3C(x)\lim_{x \rightarrow 3^{-}} C(x).

STEP 3

Define the cost function C(x)C(x) based on the given pricing structure.
C(x)={$0.34for 0<x1$0.34+$0.25for 1<x2$0.34+2×$0.25for 2<x3 C(x) = \begin{cases} \$0.34 & \text{for } 0 < x \leq 1 \\ \$0.34 + \$0.25 & \text{for } 1 < x \leq 2 \\ \$0.34 + 2 \times \$0.25 & \text{for } 2 < x \leq 3 \\ \end{cases}

STEP 4

Determine the cost for weights approaching 3 ounces from the left. This means we consider the interval 2<x<32 < x < 3.
For 2<x<32 < x < 3: C(x)=$0.34+2×$0.25=$0.34+$0.50=$0.84 C(x) = \$0.34 + 2 \times \$0.25 = \$0.34 + \$0.50 = \$0.84

STEP 5

Evaluate the limit limx3C(x)\lim_{x \rightarrow 3^{-}} C(x).
Since C(x)C(x) is constant in the interval 2<x<32 < x < 3, as xx approaches 3 from the left, C(x)C(x) remains $0.84\$0.84.
limx3C(x)=0.84 \lim_{x \rightarrow 3^{-}} C(x) = 0.84
Therefore, the answer to the problem is:
limx3C(x)=$0.84 \boxed{\lim_{x \rightarrow 3^{-}} C(x) = \$0.84}

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